# # Formal test of the quantile routine for survfit library(survival) aeq <- function(x, y, ...) all.equal(as.vector(x), as.vector(y), ...) # There are 8 cases: strata Y/N, ncol(surv) >1, conf.int = T/F # Subcase: the quantile exactly agrees with a horizontal segment of # the curve or not. # First do the 4 cases where fit$surv is a vector # test1 <- data.frame(time= c(9, 3,1,1,6,6,8, 10), status=c(1,NA,1,0,1,1,0, 0), x= c(0, 2,1,1,1,0,0, 0)) # True survival = (6/7) * (3/5) * (1/2) for overall # The q's are chosen to include a point < first jump, mid, after last jump, # and exact intersections with the "flats" of the curve. # qq <- c(13/14, 6/7, 2/3, .5, 9/35, .1) # Nothing on the right hand side, simple survival (no strata) fit1 <- survfit(Surv(time, status) ~ 1, test1, conf.type='none') aeq(quantile(fit1, 1-qq), c(1, 3.5, 6, 9, 9.5, NA)) #without conf.int fit2 <- survfit(Surv(time, status) ~ 1, test1) #with conf.int aeq(quantile(fit2, 1-qq), list(quantile = c(1, 3.5, 6, 9, 9.5, NA), lower = c(1,1,1,6,6,9), upper = rep(as.numeric(NA), 6)), check.attributes=FALSE) aeq(quantile(fit2, 1-qq, FALSE), c(1, 3.5, 6, 9, 9.5, NA)) # Now a variable on the right (strata in the result) # curve 0: (t=6, S=3/4), (t=9, S=3/8) # curve 1: (t=1, S=2/3), (t=6, S= 0) fit1 <- survfit(Surv(time, status) ~ x, test1, conf.type='none') aeq(quantile(fit1, 1-qq), matrix(c(6,6,9,9,NA,NA, 1,1,3.5, 6,6,6), nrow=2, byrow=T)) fit2 <- survfit(Surv(time, status) ~ x, test1) aeq(quantile(fit2, 1-qq, FALSE), matrix(c(6,6,9,9,NA,NA, 1,1,3.5, 6,6,6), nrow=2, byrow=T)) temp <- quantile(fit2, 1-qq) aeq(temp$quantile, matrix(c(6,6,9,9,NA,NA, 1,1,3.5, 6,6,6), nrow=2, byrow=T)) aeq(temp$lower, matrix(c(6,6,6,6,9,9, 1,1,1,1, NA,NA), nrow=2, byrow=T)) aeq(temp$upper, rep(as.numeric(NA), 12)) # Second major case set -- a survfit object where fit$surv is a matrix # This arises from coxph models # There is only 1 subject with ph.ecog=3 which is a nice edge case cfit <- coxph(Surv(time, status) ~ age + strata(ph.ecog), lung) sfit <- survfit(cfit, newdata=data.frame(age=c(50, 70))) qtot <- quantile(sfit, qq) for (i in 1:4) { for (j in 1:2) { temp <- quantile(sfit[i,j], qq) print(c(aeq(qtot$quantile[i,j,], temp$quantile), aeq(qtot$upper[i,j,], temp$upper), aeq(qtot$lower[i,j,], temp$lower))) } } temp <- quantile(sfit, qq, conf.int=FALSE) all.equal(qtot$quantile, temp)