set.seed(14235) test_that("corner cases work as expected", { expect_equal( inclusion_prob(0, 0), 0 ) expect_equal( inclusion_prob(1:3, c(0, 1, 0), factor(c(2, 2, 2), levels = 1:3)), 1:3 / 6 ) expect_equal( inclusion_prob(1:6, c(0, 3), c(1, 1, 2, 1, 2, 2)), c(0, 0, 1, 0, 1, 1) ) expect_equal( inclusion_prob(numeric(0), c(0, 0), factor(integer(0), 1:2)), numeric(0) ) expect_equal( inclusion_prob(rep(1, 6), c(2, 1), c(1, 1, 2, 1, 2, 2)), c(2, 2, 1, 2, 1, 1) / 3 ) expect_equal( inclusion_prob(c(0, 1, 1, 1 + 1e-4), 3), c(0, 1, 1, 1) ) expect_equal( inclusion_prob(c(0, 1, 1, 1 - 1e-4), 3), c(0, 1, 1, 1) ) }) test_that("argument checking works", { expect_error(inclusion_prob(-1:4, c(2, 2), gl(2, 3))) expect_error(inclusion_prob(c(NA, 1:5), c(2, 2), gl(2, 3))) expect_error(inclusion_prob(numeric(0), c(2, 2), gl(2, 3))) expect_error(inclusion_prob(numeric(0), 0, factor(integer(0)))) expect_error(inclusion_prob(c(0, 0, 1:4), c(2, 2), gl(2, 3))) expect_error(inclusion_prob(c(0, 0, 1:4), 5)) expect_error(inclusion_prob(1:6, c(-2, 2), gl(2, 3))) expect_error(inclusion_prob(1:6, c(NA, 2), gl(2, 3))) expect_error(inclusion_prob(1:6, integer(0), gl(2, 3))) expect_error(inclusion_prob(1:6, c(2, 2))) expect_error(inclusion_prob(1:6, c(2, 2), gl(2, 2))) expect_error(inclusion_prob(1:6, c(2, 2), gl(2, 3)[c(1:5, 7)])) expect_error(inclusion_prob(1:6, c(2, 2), gl(2, 3), alpha = c(0, 1.5))) expect_error(inclusion_prob(1:6, c(2, 2), gl(2, 3), alpha = c(0, NA))) expect_error(inclusion_prob(1:6, c(2, 2), gl(2, 3), alpha = c(0, 0, 0))) expect_error(inclusion_prob(1:6, c(2, 2), gl(2, 3), alpha = integer(0))) expect_error(inclusion_prob(1:6, 2, alpha = c(0, 0))) expect_error(inclusion_prob(1:6, 2, cutoff = 3)) expect_error(inclusion_prob(1:6, 2, cutoff = numeric(0))) expect_error(inclusion_prob(1:6, 2, cutoff = 1:3)) expect_error(inclusion_prob(1:6, 2, cutoff = 0)) expect_error(inclusion_prob(1:6, 2, cutoff = NA)) }) test_that("inclusion probs are correct with different rounds of TA removal", { # no rounds x <- c(0:4, 10:8, 5:7, 0) expect_equal(inclusion_prob(x, 4), x / 55 * 4) # one round x <- c(x, 100) expect_equal(inclusion_prob(x, 4), c(x[1:12] / 55 * 3, 1)) # two rounds x <- c(20, x) expect_equal(inclusion_prob(x, 5), c(1, x[2:13] / 55 * 3, 1)) # should agree with design weights samp <- sps(x, c(4, 3), gl(2, 7)) expect_equal( 1 / inclusion_prob(x, c(4, 3), gl(2, 7))[samp], weights(samp) ) # strata should be independent expect_equal( inclusion_prob(x, c(4, 3), gl(2, 7)), c(inclusion_prob(x[1:7], 4), inclusion_prob(x[8:14], 3)) ) }) test_that("results agree with sampling::inclusionprobabilities()", { expect_equal( inclusion_prob(1:20, 12), c(1:16 / 136 * 8, rep(1, 4)) ) # sampling::inclusionprobabilities() gives a warning expect_equal( inclusion_prob(0:20, 12), c(0:16 / 136 * 8, rep(1, 4)) ) expect_equal( inclusion_prob(c(1, 2, 5, 5, 5, 10, 4, 1), 6), c(0.25, 0.5, 1, 1, 1, 1, 1, 0.25) ) # sampling::inclusionprob() != inclusion_prob() with this vector # with the default alpha x <- c(100, 25, 94, 23, 55, 6, 80, 65, 48, 76, 31, 99, 45, 39, 28, 18, 54, 78, 4, 33) expect_equal( inclusion_prob(x, 10), c(1, x[-1] / sum(x[-1]) * 9) ) expect_equal( inclusion_prob(x, 10, alpha = 0), x / sum(x) * 10 ) }) test_that("TAs are added with alpha", { x <- c(0, 4, 1, 4, 5) expect_equal( inclusion_prob(rep(x, 3), c(3, 3, 3), gl(3, 5), alpha = c(0.1, 0.15, 0.2)), c(x[-5] / 9 * 2, 1, x[1] / 5, 1, x[3:4] / 5, 1, 0, 1, 0, 1, 1) ) # partial ordering doesn't break ties correctly x <- c(1, 2, 2, 2, 3) expect_equal( inclusion_prob(rep(x, 3), c(3, 3, 3), gl(3, 5), alpha = c(0.15, 0.5, 0.6)), c(x[-5] / 7 * 2, 1, 0.2, 1, 0.4, 0.4, 1, 0, 1, 1, 0, 1) ) # alpha = 1 adds TA units in order x <- c(4, 3, 4, 2, 1, 0) expect_equal( inclusion_prob(rep(x, 6), 0:5, gl(6, 6), 1), c(0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 1, 1, 0, 0, 0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 1, 1, 0) ) }) test_that("inclusion probs are a fixed point", { x <- 1:10 p <- inclusion_prob(x, 5) expect_equal(p, inclusion_prob(p, 5)) x <- c(0, 4, 1, 4, 5) p <- inclusion_prob(x, 3, alpha = 0.15) expect_equal(p, inclusion_prob(p, 3)) }) test_that("n, alpha, and cutoff recycle", { x <- 1:10 expect_equal( inclusion_prob(x, 3, gl(2, 5)), inclusion_prob(x, c(3, 3), gl(2, 5)) ) expect_equal( inclusion_prob(x, 3, gl(2, 5), alpha = 0.5), inclusion_prob(x, 3, gl(2, 5), alpha = c(0.5, 0.5)) ) x <- rep(1:5, 2) expect_equal( inclusion_prob(x, 3, gl(2, 5), cutoff = 4), inclusion_prob(x, 3, gl(2, 5), cutoff = c(4, 4)) ) }) test_that("cutoff is the same as removing units", { x <- 1:20 expect_equal(inclusion_prob(x[x < 18], 9), inclusion_prob(x, 12, cutoff = 18)[1:17]) expect_equal(inclusion_prob(x[x < 18], 9, alpha = 0.1), inclusion_prob(x, 12, cutoff = 18, alpha = 0.1)[1:17]) }) test_that("cutoff agrees with alpha", { x <- c(0, 1, 2, 3, 2, 4, 3) expect_equal(inclusion_prob(x, 3, alpha = 0.2), inclusion_prob(x, 3, cutoff = 4)) expect_equal(inclusion_prob(x, 3, alpha = 0.625), inclusion_prob(x, 3, cutoff = 3)) expect_equal(inclusion_prob(x, 3, alpha = 0.625, cutoff = 3), inclusion_prob(x, 3, cutoff = 3)) })