R Under development (unstable) (2024-10-16 r87241 ucrt) -- "Unsuffered Consequences"
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> library(mbbefd)
Loading required package: fitdistrplus
Loading required package: MASS
Loading required package: survival
Loading required package: alabama
Loading required package: numDeriv
Loading required package: Rcpp
Package:  mbbefd
Version:  0.8.12
Date:     
BugReport: https://github.com/spedygiorgio/mbbefd/issues


> library(fitdistrplus)
> 
> 
> #oiunif
> n <- 1e3
> nboot <- 1000
> nboot <- 10
> x <- roiunif(n, 1/6)
> f1 <- fitDR(x, "oiunif", method="mle")
Warning message:
In fitdist(x, distr = dist, method = method, start = start, lower = 0,  :
  The doiunif function should return a vector of with NaN values when input has inconsistent values and not raise an error
> summary(f1)
Fitting of the distribution ' oiunif ' by maximum likelihood 
Parameters : 
   estimate Std. Error
p1    0.175 0.01201529
Loglikelihood:  -463.7264   AIC:  929.4529   BIC:  934.3606 
> summary(fitdist(x, "oiunif", method="mle", start=list(p1=1/2))) #check
Fitting of the distribution ' oiunif ' by maximum likelihood 
Parameters : 
    estimate Std. Error
p1 0.1750015 0.01201537
Loglikelihood:  -463.7264   AIC:  929.4529   BIC:  934.3606 
Warning message:
In fitdist(x, "oiunif", method = "mle", start = list(p1 = 1/2)) :
  The doiunif function should return a vector of with NaN values when input has inconsistent values and not raise an error
> 
> b1 <- bootDR(f1, niter=nboot, silent=FALSE)
Warning message:
In fitdist(x, distr = dist, method = method, start = start, lower = 0,  :
  The doiunif function should return a vector of with NaN values when input has inconsistent values and not raise an error
> summary(b1)
Parametric bootstrap medians and 95% percentile CI 
  Median     2.5%    97.5% 
0.173000 0.153225 0.190000 
> 
> plot(b1)
> abline(v=1/6, col="red")
> 
> hist(b1$estim[,1])
> abline(v=1/6, col="red")
> 
> 
> f2 <- fitDR(x, "oiunif", method="tlmme")
Warning message:
In fitdist(x, distr = dist, method = method, start = start, lower = 0,  :
  The doiunif function should return a vector of with NaN values when input has inconsistent values and not raise an error
> 
> 
> 
> proc.time()
   user  system elapsed 
   1.18    0.25    1.42