R Under development (unstable) (2024-09-21 r87186 ucrt) -- "Unsuffered Consequences"
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> 
> library(glmm)
Loading required package: trust
Loading required package: mvtnorm
Loading required package: Matrix
Loading required package: parallel
Loading required package: doParallel
Loading required package: foreach
Loading required package: iterators
> 
> #First, define checks for bernoulli
> cum <- function(eta){ 
+ 	if(eta>0) eta+log1p(exp(-eta))
+ 	else log1p(exp(eta))}
> cum<-Vectorize(cum)
> cp <- function(eta) {1/(1+exp(-eta))}
> cpp<-function(eta) {(1/(1+exp(-eta)))*(1/(1+exp(eta)))}
> 
> 
> #check cum3 for a vector containing both positive and negative values of eta
> eta<-seq(-1,1,.1)
> neta<-length(eta)
> ntrials <- wts<-rep(1,neta)
> that<-.C(glmm:::C_cum3,eta=as.double(eta),neta=as.integer(neta), type=as.integer(1), ntrials=as.integer(ntrials), wts=as.double(wts),cumout=double(1))
> all.equal(sum(cum(eta)),that$cumout)
[1] TRUE
> 
> #check cp3
> that<-.C(glmm:::C_cp3,eta=as.double(eta),neta=as.integer(neta),type=as.integer(1), ntrials=as.integer(ntrials), cpout=double(neta))
> all.equal(cp(eta),that$cpout)
[1] TRUE
> 
> #check cpp3
> that<-.C(glmm:::C_cpp3,eta=as.double(eta),neta=as.integer(neta),type=as.integer(1), ntrials=as.integer(ntrials), cppout=double(neta))
> all.equal(cpp(eta),that$cppout)
[1] TRUE
> 
> ######################
> #now move onto Poisson
> cum <- function(eta) exp(eta)
> cp <- function(eta) exp(eta)
> cpp<-function(eta) exp(eta)
> eta<-c(4.5,5,5.5)
> neta<-length(eta)
> ntrials <- wts<-rep(1,neta)
> 
> #check cum3
> that<-.C(glmm:::C_cum3, eta=as.double(eta), neta=as.integer(neta), type=as.integer(2), ntrials=as.integer(ntrials), wts=as.double(wts), cumout=double(1))
> all.equal(sum(cum(eta)),that$cumout)
[1] TRUE
> 
> #check cp3
> that<-.C(glmm:::C_cp3,eta=as.double(eta), neta=as.integer(neta), type=as.integer(2), ntrials=as.integer(ntrials), cpout=double(neta))
> all.equal(cp(eta), that$cpout)
[1] TRUE
> 
> #check cpp3
> that<-.C(glmm:::C_cpp3,eta=as.double(eta),neta=as.integer(neta),type=as.integer(2), ntrials=as.integer(ntrials), cppout=double(neta))
> all.equal(cpp(eta), that$cppout)
[1] TRUE
> 
> 
> proc.time()
   user  system elapsed 
   1.28    0.17    1.39