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Type 'q()' to quit R. > l2_dist <- function(x, y) sqrt(sum((x-y)^2)) > > status_codes <- clarabel::solver_status_descriptions() > > if ( requireNamespace("tinytest", quietly = TRUE) ){ + tinytest::test_package("clarabel") + } test_api_dimension.R.......... 0 tests test_api_dimension.R.......... 0 tests cones: [ZeroConeT(1), NonnegativeConeT(5)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 4 constraints = 6 nnz(P) = 0 nnz(A) = 0 cones (total) = 2 : Zero = 1, numel = 1 : Nonnegative = 1, numel = 5 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -0.0000e+00 0.00e+00 1.00e+00 0.00e+00 1.00e+00 1.00e+00 ------ 1 +0.0000e+00 -0.0000e+00 0.00e+00 2.24e-02 0.00e+00 1.00e-02 1.00e-02 9.90e-01 2 +0.0000e+00 -0.0000e+00 0.00e+00 2.24e-04 0.00e+00 1.00e-04 1.00e-04 9.90e-01 3 +0.0000e+00 -0.0000e+00 0.00e+00 2.24e-06 0.00e+00 1.00e-06 1.00e-06 9.90e-01 4 +0.0000e+00 -0.0000e+00 0.00e+00 2.24e-08 0.00e+00 1.00e-08 1.00e-08 9.90e-01 5 +0.0000e+00 -0.0000e+00 0.00e+00 2.24e-10 0.00e+00 1.00e-10 1.00e-10 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 239µs test_api_dimension.R.......... 0 tests test_api_dimension.R.......... 1 tests OK test_api_dimension.R.......... 1 tests OK test_api_dimension.R.......... 2 tests OK test_api_dimension.R.......... 2 tests OK test_api_dimension.R.......... 2 tests OK test_api_dimension.R.......... 3 tests OK test_api_dimension.R.......... 3 tests OK test_api_dimension.R.......... 3 tests OK test_api_dimension.R.......... 4 tests OK test_api_dimension.R.......... 4 tests OK test_api_dimension.R.......... 4 tests OK test_api_dimension.R.......... 5 tests OK test_api_dimension.R.......... 5 tests OK test_api_dimension.R.......... 5 tests OK test_api_dimension.R.......... 6 tests OK test_api_dimension.R.......... 6 tests OK test_api_dimension.R.......... 6 tests OK test_api_dimension.R.......... 7 tests OK test_api_dimension.R.......... 7 tests OK test_api_dimension.R.......... 7 tests OK cones: [ZeroConeT(1), NonnegativeConeT(2), NonnegativeConeT(3)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 4 constraints = 6 nnz(P) = 0 nnz(A) = 0 cones (total) = 3 : Zero = 1, numel = 1 : Nonnegative = 2, numel = (2,3) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -0.0000e+00 0.00e+00 1.00e+00 0.00e+00 1.00e+00 1.00e+00 ------ 1 +0.0000e+00 -0.0000e+00 0.00e+00 2.24e-02 0.00e+00 1.00e-02 1.00e-02 9.90e-01 2 +0.0000e+00 -0.0000e+00 0.00e+00 2.24e-04 0.00e+00 1.00e-04 1.00e-04 9.90e-01 3 +0.0000e+00 -0.0000e+00 0.00e+00 2.24e-06 0.00e+00 1.00e-06 1.00e-06 9.90e-01 4 +0.0000e+00 -0.0000e+00 0.00e+00 2.24e-08 0.00e+00 1.00e-08 1.00e-08 9.90e-01 5 +0.0000e+00 -0.0000e+00 0.00e+00 2.24e-10 0.00e+00 1.00e-10 1.00e-10 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 73.6µs test_api_dimension.R.......... 7 tests OK test_api_dimension.R.......... 8 tests OK 99ms test_basic_eq_constrained.R... 0 tests test_basic_eq_constrained.R... 0 tests test_basic_eq_constrained.R... 0 tests test_basic_eq_constrained.R... 0 tests test_basic_eq_constrained.R... 0 tests test_basic_eq_constrained.R... 0 tests test_basic_eq_constrained.R... 0 tests cones: [ZeroConeT(2)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 3 constraints = 2 nnz(P) = 3 nnz(A) = 4 cones (total) = 1 : Zero = 1, numel = 2 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +1.0000e+00 +1.0000e+00 0.00e+00 6.50e-17 9.20e-17 1.00e+00 1.00e+00 ------ 0 +1.0000e+00 +1.0000e+00 0.00e+00 6.50e-17 9.20e-17 1.00e+00 1.00e+00 ------ --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 55.8µs test_basic_eq_constrained.R... 0 tests test_basic_eq_constrained.R... 0 tests test_basic_eq_constrained.R... 1 tests OK test_basic_eq_constrained.R... 2 tests OK test_basic_eq_constrained.R... 2 tests OK test_basic_eq_constrained.R... 2 tests OK test_basic_eq_constrained.R... 2 tests OK test_basic_eq_constrained.R... 2 tests OK test_basic_eq_constrained.R... 2 tests OK cones: [ZeroConeT(4)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 3 constraints = 4 nnz(P) = 3 nnz(A) = 10 cones (total) = 1 : Zero = 1, numel = 4 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +3.8333e-01 +1.3607e+08 1.36e+08 3.46e-01 2.06e-16 1.00e+00 1.00e+00 ------ 1 +3.8333e-01 +6.8716e+09 6.87e+09 3.46e-01 2.67e-16 2.06e+02 2.06e-02 5.66e-01 2 +3.8332e-01 +6.7383e+11 6.74e+11 3.46e-01 3.65e-16 1.77e+07 1.77e-01 3.37e-01 3 +3.8333e-01 +1.3638e+08 1.36e+08 3.46e-01 1.41e-16 1.36e+08 6.54e+12 9.90e-01 4 +3.8333e-01 +5.4903e+08 5.49e+08 3.46e-01 3.51e-17 5.49e+08 7.08e+11 9.90e-01 5 +3.8333e-01 +4.5706e+09 4.57e+09 3.46e-01 1.25e-16 4.57e+09 6.92e+10 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = PrimalInfeasible solve time = 86.4µs test_basic_eq_constrained.R... 2 tests OK test_basic_eq_constrained.R... 3 tests OK test_basic_eq_constrained.R... 3 tests OK test_basic_eq_constrained.R... 3 tests OK test_basic_eq_constrained.R... 3 tests OK test_basic_eq_constrained.R... 3 tests OK test_basic_eq_constrained.R... 3 tests OK test_basic_eq_constrained.R... 3 tests OK cones: [ZeroConeT(2)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 3 constraints = 2 nnz(P) = 2 nnz(A) = 4 cones (total) = 1 : Zero = 1, numel = 2 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 -1.0000e+08 +3.0000e+00 3.33e+07 2.00e-16 1.00e-08 1.00e+00 1.00e+00 ------ 1 -5.0500e+09 +3.0000e+00 1.68e+09 1.92e-16 1.98e-10 2.06e+02 2.06e-02 5.66e-01 2 -4.9529e+11 +2.9999e+00 1.65e+11 1.96e-16 2.02e-12 1.81e+07 1.81e-01 3.37e-01 3 -1.0019e+08 +3.0000e+00 3.34e+07 1.99e-16 9.98e-09 1.00e+08 7.13e+12 9.90e-01 4 -1.0014e+10 +3.0000e+00 3.34e+09 1.96e-16 9.99e-11 1.00e+10 7.14e+10 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = DualInfeasible solve time = 55.6µs test_basic_eq_constrained.R... 3 tests OK test_basic_eq_constrained.R... 4 tests OK 1.1s test_basic_expcone.R.......... 0 tests test_basic_expcone.R.......... 0 tests test_basic_expcone.R.......... 0 tests test_basic_expcone.R.......... 0 tests cones: [ExponentialConeT, ZeroConeT(2)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 3 constraints = 5 nnz(P) = 0 nnz(A) = 5 cones (total) = 2 : Zero = 1, numel = 2 : Exponential = 1, numel = 3 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -0.0000e+00 0.00e+00 9.89e-01 5.04e-01 1.00e+00 1.00e+00 ------ 1 +3.3353e+00 +6.8900e+00 1.07e+00 9.14e-01 8.95e-02 4.53e+00 2.14e-01 7.92e-01 2 +1.5946e+01 +3.3184e+01 1.08e+00 6.60e-01 1.78e-02 1.81e+01 4.59e-02 7.92e-01 3 +2.4261e+01 +5.1084e+01 1.11e+00 2.30e-01 5.04e-03 2.73e+01 1.13e-02 7.92e-01 4 +7.1045e+00 +1.3831e+01 9.47e-01 5.63e-02 1.50e-03 6.88e+00 3.38e-03 7.92e-01 5 -1.9077e+00 -4.4928e-01 1.46e+00 1.14e-02 3.05e-04 1.49e+00 7.24e-04 7.92e-01 6 -4.2883e+00 -3.9751e+00 7.88e-02 2.42e-03 6.44e-05 3.20e-01 1.55e-04 7.92e-01 7 -4.9836e+00 -4.9749e+00 1.76e-03 6.68e-05 1.78e-06 8.95e-03 4.30e-06 9.80e-01 8 -4.9996e+00 -4.9993e+00 4.91e-05 1.85e-06 4.94e-08 2.51e-04 1.19e-07 9.80e-01 9 -5.0000e+00 -5.0000e+00 1.38e-06 5.14e-08 1.37e-09 7.03e-06 3.31e-09 9.80e-01 10 -5.0000e+00 -5.0000e+00 3.84e-08 1.43e-09 3.80e-11 1.96e-07 9.19e-11 9.80e-01 11 -5.0000e+00 -5.0000e+00 8.23e-09 3.06e-10 8.14e-12 4.21e-08 1.97e-11 7.92e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 191µs test_basic_expcone.R.......... 0 tests test_basic_expcone.R.......... 1 tests OK test_basic_expcone.R.......... 2 tests OK test_basic_expcone.R.......... 3 tests OK test_basic_expcone.R.......... 3 tests OK test_basic_expcone.R.......... 3 tests OK cones: [ExponentialConeT, ZeroConeT(2)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 3 constraints = 5 nnz(P) = 0 nnz(A) = 5 cones (total) = 2 : Zero = 1, numel = 2 : Exponential = 1, numel = 3 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -0.0000e+00 0.00e+00 8.18e-01 5.04e-01 1.00e+00 1.00e+00 ------ 1 +2.4937e+00 +3.8431e+00 5.41e-01 1.92e-01 8.90e-02 1.93e+00 2.14e-01 7.92e-01 2 +2.6649e+01 +5.1053e+01 9.16e-01 2.31e-02 5.67e-03 2.50e+01 1.41e-02 9.80e-01 3 +9.0928e+02 +1.8371e+03 1.02e+00 7.27e-04 1.56e-04 9.28e+02 3.90e-04 9.80e-01 4 +4.1733e+03 +8.6977e+03 1.08e+00 1.64e-04 3.37e-05 4.52e+03 8.39e-05 7.92e-01 5 +1.9879e+04 +4.0628e+04 1.04e+00 3.40e-05 7.21e-06 2.07e+04 1.80e-05 7.92e-01 6 +7.7862e+05 +1.6258e+06 1.09e+00 9.89e-07 2.03e-07 8.47e+05 5.06e-07 9.80e-01 7 +4.1803e+06 +7.9502e+06 9.02e-01 1.78e-07 4.33e-08 3.77e+06 1.08e-07 7.92e-01 8 +1.8688e+07 +3.7215e+07 9.91e-01 4.18e-08 9.50e-09 1.85e+07 2.37e-08 7.89e-01 9 +8.9399e+07 +1.7155e+08 9.19e-01 8.42e-09 2.03e-09 8.21e+07 5.05e-09 7.92e-01 10 +4.1046e+08 +8.1386e+08 9.83e-01 1.91e-09 4.44e-10 4.03e+08 1.11e-09 7.89e-01 11 +1.8933e+09 +3.6619e+09 9.34e-01 4.02e-10 9.78e-11 1.77e+09 2.37e-10 7.92e-01 --------------------------------------------------------------------------------------------- Terminated with status = PrimalInfeasible solve time = 142µs test_basic_expcone.R.......... 3 tests OK test_basic_expcone.R.......... 4 tests OK test_basic_expcone.R.......... 4 tests OK test_basic_expcone.R.......... 4 tests OK test_basic_expcone.R.......... 4 tests OK test_basic_expcone.R.......... 4 tests OK test_basic_expcone.R.......... 4 tests OK cones: [ExponentialConeT] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 3 constraints = 3 nnz(P) = 0 nnz(A) = 3 cones (total) = 1 : Exponential = 1, numel = 3 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -0.0000e+00 0.00e+00 1.00e+00 5.04e-01 1.00e+00 1.00e+00 ------ 1 -2.0419e-01 -0.0000e+00 2.04e-01 1.33e-01 1.10e-01 5.21e-01 2.45e-01 7.92e-01 2 -4.6250e+01 -0.0000e+00 4.63e+01 1.01e-02 1.58e-02 5.06e+01 3.39e-02 9.75e-01 3 -4.1213e+02 -0.0000e+00 4.12e+02 2.76e-04 4.38e-04 4.13e+02 9.41e-04 9.80e-01 4 -9.5781e+03 -0.0000e+00 9.58e+03 7.64e-06 1.22e-05 9.58e+03 2.61e-05 9.80e-01 5 -2.7489e+05 -0.0000e+00 2.75e+05 2.12e-07 3.37e-07 2.75e+05 7.24e-07 9.80e-01 6 -8.6448e+06 -0.0000e+00 8.64e+06 5.88e-09 9.35e-09 8.64e+06 2.01e-08 9.80e-01 7 -2.8548e+08 -0.0000e+00 2.85e+08 1.63e-10 2.59e-10 2.85e+08 5.57e-10 9.80e-01 8 -1.4345e+10 -0.0000e+00 1.43e+10 3.25e-12 5.16e-12 1.43e+10 1.11e-11 9.80e-01 --------------------------------------------------------------------------------------------- Terminated with status = DualInfeasible solve time = 89.8µs test_basic_expcone.R.......... 4 tests OK test_basic_expcone.R.......... 5 tests OK 40ms test_basic_genpowcone.R....... 0 tests test_basic_genpowcone.R....... 0 tests test_basic_genpowcone.R....... 0 tests test_basic_genpowcone.R....... 0 tests test_basic_genpowcone.R....... 0 tests test_basic_genpowcone.R....... 0 tests test_basic_genpowcone.R....... 0 tests test_basic_genpowcone.R....... 0 tests test_basic_genpowcone.R....... 0 tests test_basic_genpowcone.R....... 0 tests test_basic_genpowcone.R....... 0 tests test_basic_genpowcone.R....... 0 tests cones: [GenPowerConeT([0.6, 0.4], 1), GenPowerConeT([0.1, 0.9], 1), ZeroConeT(2)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 6 constraints = 8 nnz(P) = 0 nnz(A) = 10 cones (total) = 3 : Zero = 1, numel = 2 : GenPower = 2, numel = (3,3) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -0.0000e+00 0.00e+00 7.43e-01 1.02e+00 1.00e+00 1.00e+00 ------ 1 -4.1106e-01 -4.3422e-01 2.32e-02 2.49e-01 3.45e-01 3.64e-01 4.12e-01 6.34e-01 2 -1.0943e+00 -1.0992e+00 4.50e-03 9.42e-02 1.21e-01 1.58e-01 1.69e-01 6.34e-01 3 -1.7009e+00 -1.6983e+00 1.55e-03 1.92e-02 2.32e-02 4.17e-02 3.83e-02 7.92e-01 4 -1.8032e+00 -1.8021e+00 5.93e-04 4.31e-03 5.14e-03 1.00e-02 7.83e-03 7.92e-01 5 -1.8344e+00 -1.8341e+00 1.67e-04 9.56e-04 1.14e-03 2.30e-03 1.62e-03 7.92e-01 6 -1.8438e+00 -1.8437e+00 2.64e-05 1.92e-04 2.28e-04 4.49e-04 3.70e-04 7.86e-01 7 -1.8447e+00 -1.8446e+00 1.27e-05 7.82e-05 9.29e-05 1.87e-04 1.42e-04 6.34e-01 8 -1.8452e+00 -1.8452e+00 2.61e-06 1.66e-05 1.97e-05 3.95e-05 3.13e-05 7.92e-01 9 -1.8453e+00 -1.8453e+00 1.27e-06 6.84e-06 8.11e-06 1.66e-05 1.19e-05 6.34e-01 10 -1.8453e+00 -1.8453e+00 2.57e-07 1.45e-06 1.72e-06 3.49e-06 2.63e-06 7.92e-01 11 -1.8453e+00 -1.8453e+00 1.23e-07 5.97e-07 7.08e-07 1.47e-06 1.00e-06 6.34e-01 12 -1.8454e+00 -1.8454e+00 2.49e-08 1.26e-07 1.50e-07 3.10e-07 2.21e-07 7.92e-01 13 -1.8454e+00 -1.8454e+00 1.17e-08 5.21e-08 6.18e-08 1.30e-07 8.41e-08 6.34e-01 14 -1.8454e+00 -1.8454e+00 2.36e-09 1.10e-08 1.31e-08 2.74e-08 1.86e-08 7.92e-01 15 -1.8454e+00 -1.8454e+00 1.09e-09 4.54e-09 5.40e-09 1.15e-08 7.07e-09 6.34e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 400.3µs test_basic_genpowcone.R....... 0 tests test_basic_genpowcone.R....... 1 tests OK test_basic_genpowcone.R....... 1 tests OK test_basic_genpowcone.R....... 2 tests OK 14ms test_basic_lp.R............... 0 tests test_basic_lp.R............... 0 tests cones: [NonnegativeConeT(3), NonnegativeConeT(3)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 3 constraints = 6 nnz(P) = 0 nnz(A) = 6 cones (total) = 2 : Nonnegative = 2, numel = (3,3) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -8.7426e+00 8.74e+00 2.27e-01 3.31e-17 1.00e+00 1.91e+00 ------ 1 -1.9601e+00 -3.2218e+00 6.44e-01 2.95e-02 6.80e-17 1.65e-01 3.37e-01 8.56e-01 2 -2.9735e+00 -3.0310e+00 1.93e-02 1.13e-03 6.82e-17 9.69e-03 1.60e-02 9.73e-01 3 -2.9997e+00 -3.0003e+00 1.92e-04 1.13e-05 3.05e-17 9.73e-05 1.61e-04 9.90e-01 4 -3.0000e+00 -3.0000e+00 1.92e-06 1.13e-07 3.05e-17 9.73e-07 1.61e-06 9.90e-01 5 -3.0000e+00 -3.0000e+00 1.92e-08 1.13e-09 1.89e-15 9.73e-09 1.61e-08 9.90e-01 6 -3.0000e+00 -3.0000e+00 1.92e-10 1.13e-11 6.81e-17 9.73e-11 1.61e-10 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 113.9µs test_basic_lp.R............... 0 tests test_basic_lp.R............... 1 tests OK test_basic_lp.R............... 1 tests OK test_basic_lp.R............... 2 tests OK test_basic_lp.R............... 2 tests OK test_basic_lp.R............... 3 tests OK test_basic_lp.R............... 4 tests OK test_basic_lp.R............... 4 tests OK test_basic_lp.R............... 4 tests OK test_basic_lp.R............... 4 tests OK cones: [NonnegativeConeT(3), NonnegativeConeT(3)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 3 constraints = 6 nnz(P) = 0 nnz(A) = 6 cones (total) = 2 : Nonnegative = 2, numel = (3,3) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -2.9142e+00 2.91e+00 7.29e-01 3.31e-17 1.00e+00 3.57e+00 ------ 1 +5.5554e-01 -2.9184e-01 8.47e-01 5.38e-01 7.45e-17 1.29e+00 1.41e+00 7.04e-01 2 +2.8173e+00 +7.9435e+01 2.72e+01 7.57e-01 8.33e-17 8.76e+01 1.20e-01 9.90e-01 3 +3.0152e+00 +7.9798e+03 2.65e+03 7.47e-01 1.24e-16 7.99e+03 1.24e-03 9.90e-01 4 +3.0152e+00 +7.9843e+05 2.65e+05 7.47e-01 1.74e-17 7.98e+05 1.24e-05 9.90e-01 5 +3.0152e+00 +7.9842e+07 2.65e+07 7.47e-01 9.39e-17 7.98e+07 1.24e-07 9.90e-01 6 +3.0152e+00 +7.9842e+09 2.65e+09 7.47e-01 7.97e-17 7.98e+09 1.24e-09 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = PrimalInfeasible solve time = 94.4µs test_basic_lp.R............... 4 tests OK test_basic_lp.R............... 5 tests OK test_basic_lp.R............... 6 tests OK test_basic_lp.R............... 7 tests OK test_basic_lp.R............... 7 tests OK test_basic_lp.R............... 7 tests OK test_basic_lp.R............... 7 tests OK cones: [NonnegativeConeT(3), NonnegativeConeT(3)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 3 constraints = 6 nnz(P) = 0 nnz(A) = 6 cones (total) = 2 : Nonnegative = 2, numel = (3,3) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +7.4983e-01 -5.9498e+00 6.70e+00 5.09e-01 5.76e-01 1.00e+00 2.12e+00 ------ 1 -2.5313e-01 -2.3276e+00 2.07e+00 2.54e-01 3.54e-01 4.72e-01 8.11e-01 6.45e-01 2 -2.2767e+02 -2.1911e+02 3.90e-02 2.48e-02 3.21e-02 5.12e+01 1.36e-01 9.72e-01 3 -4.2035e+03 -3.5181e+03 1.95e-01 3.00e-04 3.91e-04 6.95e+02 1.69e-03 9.88e-01 4 -4.2069e+05 -3.5134e+05 1.97e-01 3.00e-06 3.91e-06 6.94e+04 1.69e-05 9.90e-01 5 -4.2070e+07 -3.5133e+07 1.97e-01 3.00e-08 3.91e-08 6.94e+06 1.69e-07 9.90e-01 6 -4.2057e+09 -3.5122e+09 1.97e-01 3.00e-10 3.91e-10 6.93e+08 1.69e-09 9.90e-01 7 -4.2057e+11 -3.5122e+11 1.97e-01 3.00e-12 3.91e-12 6.93e+10 1.69e-11 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = DualInfeasible solve time = 81.9µs test_basic_lp.R............... 7 tests OK test_basic_lp.R............... 8 tests OK test_basic_lp.R............... 9 tests OK test_basic_lp.R............... 10 tests OK test_basic_lp.R............... 10 tests OK test_basic_lp.R............... 10 tests OK test_basic_lp.R............... 10 tests OK test_basic_lp.R............... 10 tests OK cones: [NonnegativeConeT(3), NonnegativeConeT(3)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 3 constraints = 6 nnz(P) = 0 nnz(A) = 5 cones (total) = 2 : Nonnegative = 2, numel = (3,3) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +4.4409e+08 -1.8002e+05 2.47e+03 9.85e-01 7.51e-06 1.00e+00 5.29e+06 ------ 1 +4.2627e+08 -1.8002e+07 2.47e+01 9.85e-01 7.51e-08 1.00e+02 5.29e+04 9.90e-01 2 -1.3559e+09 -1.8002e+09 3.28e-01 9.67e-01 7.51e-10 1.00e+04 5.29e+02 9.90e-01 3 -1.7958e+11 -1.8002e+11 2.47e-03 2.17e-01 7.51e-12 1.00e+06 5.29e+00 9.90e-01 4 -1.8002e+13 -1.8002e+13 1.91e-05 2.76e-03 7.51e-14 1.00e+08 5.29e-02 9.90e-01 5 -1.7995e+15 -1.7995e+15 5.31e-06 2.83e-05 7.67e-16 1.00e+10 5.41e-04 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = DualInfeasible solve time = 86µs test_basic_lp.R............... 10 tests OK test_basic_lp.R............... 11 tests OK test_basic_lp.R............... 12 tests OK test_basic_lp.R............... 13 tests OK 48ms test_basic_powcone.R.......... 0 tests test_basic_powcone.R.......... 0 tests test_basic_powcone.R.......... 0 tests test_basic_powcone.R.......... 0 tests test_basic_powcone.R.......... 0 tests test_basic_powcone.R.......... 0 tests test_basic_powcone.R.......... 0 tests test_basic_powcone.R.......... 0 tests test_basic_powcone.R.......... 0 tests test_basic_powcone.R.......... 0 tests test_basic_powcone.R.......... 0 tests test_basic_powcone.R.......... 0 tests cones: [PowerConeT(0.6), PowerConeT(0.1), ZeroConeT(2)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 6 constraints = 8 nnz(P) = 0 nnz(A) = 10 cones (total) = 3 : Zero = 1, numel = 2 : Power = 2, numel = (3,3) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -0.0000e+00 0.00e+00 7.43e-01 1.02e+00 1.00e+00 1.00e+00 ------ 1 -7.2016e-01 -7.0464e-01 1.55e-02 1.57e-01 2.11e-01 2.71e-01 2.63e-01 7.92e-01 2 -1.8008e+00 -1.7671e+00 1.90e-02 2.13e-02 2.58e-02 7.82e-02 3.52e-02 9.80e-01 3 -1.8433e+00 -1.8426e+00 3.44e-04 5.91e-04 7.02e-04 1.87e-03 9.76e-04 9.80e-01 4 -1.8448e+00 -1.8447e+00 7.21e-05 1.27e-04 1.51e-04 3.98e-04 2.09e-04 7.92e-01 5 -1.8452e+00 -1.8452e+00 1.52e-05 2.72e-05 3.23e-05 8.48e-05 4.49e-05 7.92e-01 6 -1.8453e+00 -1.8453e+00 3.21e-06 5.83e-06 6.92e-06 1.81e-05 9.62e-06 7.92e-01 7 -1.8453e+00 -1.8453e+00 6.77e-07 1.25e-06 1.48e-06 3.86e-06 2.06e-06 7.92e-01 8 -1.8454e+00 -1.8454e+00 1.43e-07 2.68e-07 3.18e-07 8.23e-07 4.42e-07 7.92e-01 9 -1.8454e+00 -1.8454e+00 3.03e-08 5.74e-08 6.81e-08 1.76e-07 9.47e-08 7.92e-01 10 -1.8454e+00 -1.8454e+00 6.41e-09 1.23e-08 1.46e-08 3.75e-08 2.03e-08 7.92e-01 11 -1.8454e+00 -1.8454e+00 1.36e-09 2.64e-09 3.13e-09 8.00e-09 4.35e-09 7.92e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 184.6µs test_basic_powcone.R.......... 0 tests test_basic_powcone.R.......... 1 tests OK test_basic_powcone.R.......... 1 tests OK test_basic_powcone.R.......... 2 tests OK 7ms test_basic_psd.R.............. 0 tests test_basic_psd.R.............. 0 tests test_basic_psd.R.............. 0 tests test_basic_psd.R.............. 0 tests cones: [PSDTriangleConeT(3)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 6 constraints = 6 nnz(P) = 6 nnz(A) = 6 cones (total) = 1 : PSDTriangle = 1, numel = 6 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +7.0000e+00 -3.3203e+00 3.11e+00 2.81e-01 7.03e-01 1.00e+00 5.64e+00 ------ 1 +2.2779e+02 -2.8988e+02 2.27e+00 1.18e-02 2.24e-02 1.22e+01 7.28e-01 9.90e-01 2 +5.4277e+01 -7.2551e+01 2.34e+00 2.64e-04 5.94e-04 3.91e+00 1.06e-01 9.90e-01 3 +1.4671e+01 -1.4575e+01 2.01e+00 5.08e-06 1.46e-05 1.14e+00 1.50e-02 9.90e-01 4 +6.3736e+00 +7.5792e-01 5.62e+00 7.59e-08 2.69e-07 2.57e-01 1.97e-03 9.90e-01 5 +4.9823e+00 +4.3330e+00 1.50e-01 8.95e-10 3.38e-09 3.14e-02 1.85e-04 9.90e-01 6 +4.8445e+00 +4.8232e+00 4.40e-03 9.22e-12 3.51e-11 1.04e-03 5.80e-06 9.90e-01 7 +4.8401e+00 +4.8399e+00 4.75e-05 2.80e-12 6.62e-12 1.13e-05 6.27e-08 9.90e-01 8 +4.8401e+00 +4.8401e+00 4.76e-07 5.93e-14 1.41e-13 1.13e-07 6.27e-10 9.90e-01 9 +4.8401e+00 +4.8401e+00 4.76e-09 9.85e-16 2.16e-15 1.13e-09 6.27e-12 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 512.7µs test_basic_psd.R.............. 0 tests test_basic_psd.R.............. 1 tests OK test_basic_psd.R.............. 2 tests OK test_basic_psd.R.............. 3 tests OK test_basic_psd.R.............. 3 tests OK test_basic_psd.R.............. 3 tests OK test_basic_psd.R.............. 3 tests OK test_basic_psd.R.............. 3 tests OK cones: [PSDTriangleConeT(3), PSDTriangleConeT(0)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 6 constraints = 6 nnz(P) = 6 nnz(A) = 6 cones (total) = 2 : PSDTriangle = 2, numel = (6,0) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +7.0000e+00 -3.3203e+00 3.11e+00 2.81e-01 7.03e-01 1.00e+00 5.64e+00 ------ 1 +2.2779e+02 -2.8988e+02 2.27e+00 1.18e-02 2.24e-02 1.22e+01 7.28e-01 9.90e-01 2 +5.4277e+01 -7.2551e+01 2.34e+00 2.64e-04 5.94e-04 3.91e+00 1.06e-01 9.90e-01 3 +1.4671e+01 -1.4575e+01 2.01e+00 5.08e-06 1.46e-05 1.14e+00 1.50e-02 9.90e-01 4 +6.3736e+00 +7.5792e-01 5.62e+00 7.59e-08 2.69e-07 2.57e-01 1.97e-03 9.90e-01 5 +4.9823e+00 +4.3330e+00 1.50e-01 8.95e-10 3.38e-09 3.14e-02 1.85e-04 9.90e-01 6 +4.8445e+00 +4.8232e+00 4.40e-03 9.22e-12 3.51e-11 1.04e-03 5.80e-06 9.90e-01 7 +4.8401e+00 +4.8399e+00 4.75e-05 2.80e-12 6.62e-12 1.13e-05 6.27e-08 9.90e-01 8 +4.8401e+00 +4.8401e+00 4.76e-07 5.93e-14 1.41e-13 1.13e-07 6.27e-10 9.90e-01 9 +4.8401e+00 +4.8401e+00 4.76e-09 9.85e-16 2.16e-15 1.13e-09 6.27e-12 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 278.7µs test_basic_psd.R.............. 3 tests OK test_basic_psd.R.............. 4 tests OK test_basic_psd.R.............. 5 tests OK test_basic_psd.R.............. 6 tests OK test_basic_psd.R.............. 6 tests OK test_basic_psd.R.............. 6 tests OK test_basic_psd.R.............. 6 tests OK test_basic_psd.R.............. 6 tests OK cones: [PSDTriangleConeT(3), PSDTriangleConeT(3)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 6 constraints = 12 nnz(P) = 6 nnz(A) = 12 cones (total) = 2 : PSDTriangle = 2, numel = (6,6) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +3.1111e+00 +3.7951e+00 2.20e-01 4.04e-01 3.50e-17 1.00e+00 1.08e+01 ------ 1 +4.2099e+01 +2.9730e+00 1.32e+01 2.79e-01 3.39e-17 8.34e+00 1.35e+00 8.83e-01 2 +6.4390e+00 +7.2982e+01 1.03e+01 4.54e-01 6.72e-17 2.56e+02 1.00e-01 9.80e-01 3 +6.7381e+00 +2.4003e+04 3.56e+03 4.53e-01 2.37e-17 2.42e+04 1.02e-03 9.90e-01 4 +6.7381e+00 +2.4173e+06 3.59e+05 4.53e-01 7.90e-17 2.42e+06 1.02e-05 9.90e-01 5 +6.7380e+00 +2.4175e+08 3.59e+07 4.53e-01 3.37e-17 2.42e+08 1.02e-07 9.90e-01 6 +6.7380e+00 +2.4175e+10 3.59e+09 4.53e-01 2.95e-17 2.42e+10 1.02e-09 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = PrimalInfeasible solve time = 345.8µs test_basic_psd.R.............. 6 tests OK test_basic_psd.R.............. 7 tests OK test_basic_psd.R.............. 7 tests OK test_basic_psd.R.............. 7 tests OK test_basic_psd.R.............. 7 tests OK test_basic_psd.R.............. 7 tests OK test_basic_psd.R.............. 7 tests OK test_basic_psd.R.............. 7 tests OK test_basic_psd.R.............. 7 tests OK test_basic_psd.R.............. 7 tests OK test_basic_psd.R.............. 7 tests OK test_basic_psd.R.............. 7 tests OK test_basic_psd.R.............. 7 tests OK test_basic_psd.R.............. 7 tests OK test_basic_psd.R.............. 7 tests OK test_basic_psd.R.............. 7 tests OK cones: [PSDTriangleConeT(2), PSDTriangleConeT(3)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 3 constraints = 9 nnz(P) = 0 nnz(A) = 25 cones (total) = 2 : PSDTriangle = 2, numel = (3,6) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 -1.3633e+00 -8.2977e+01 5.99e+01 5.94e-17 1.22e-01 1.00e+00 1.33e+01 ------ 1 -1.5650e+00 -5.7983e+00 2.71e+00 1.17e-16 6.99e-03 4.69e-02 6.99e-01 9.48e-01 2 -2.9817e+00 -3.6938e+00 2.39e-01 1.28e-16 1.36e-03 4.18e-02 1.37e-01 8.64e-01 3 -3.0814e+00 -3.2171e+00 4.40e-02 7.00e-17 2.47e-04 8.96e-03 2.67e-02 8.23e-01 4 -3.1494e+00 -3.1713e+00 6.96e-03 5.55e-16 3.81e-05 1.61e-03 4.39e-03 8.49e-01 5 -3.1534e+00 -3.1551e+00 5.11e-04 7.70e-16 2.82e-06 1.34e-04 3.26e-04 9.34e-01 6 -3.1535e+00 -3.1536e+00 1.70e-05 7.40e-16 9.44e-08 4.82e-06 1.09e-05 9.70e-01 7 -3.1535e+00 -3.1535e+00 1.43e-06 8.89e-16 7.93e-09 4.12e-07 9.16e-07 9.18e-01 8 -3.1535e+00 -3.1535e+00 7.20e-08 2.21e-15 4.06e-10 2.40e-08 4.69e-08 9.59e-01 9 -3.1535e+00 -3.1535e+00 3.19e-09 3.13e-14 1.80e-11 1.08e-09 2.08e-09 9.58e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 382.5µs test_basic_psd.R.............. 7 tests OK test_basic_psd.R.............. 8 tests OK test_basic_psd.R.............. 9 tests OK 16ms test_basic_qp.R............... 0 tests test_basic_qp.R............... 0 tests test_basic_qp.R............... 0 tests test_basic_qp.R............... 0 tests test_basic_qp.R............... 0 tests test_basic_qp.R............... 0 tests cones: [ZeroConeT(1), NonnegativeConeT(4)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 2 constraints = 5 nnz(P) = 2 nnz(A) = 6 cones (total) = 2 : Zero = 1, numel = 1 : Nonnegative = 1, numel = 4 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 -3.2878e-01 -1.8973e+01 1.86e+01 9.76e-17 9.77e-17 1.00e+00 1.77e+00 ------ 1 -5.7453e-01 -1.8040e+00 1.23e+00 5.92e-17 3.59e-17 6.08e-02 1.15e-01 9.44e-01 2 -6.4203e-01 -7.5345e-01 1.11e-01 3.64e-17 0.00e+00 5.21e-03 8.97e-03 9.90e-01 3 -6.4286e-01 -6.4541e-01 2.55e-03 3.26e-17 1.60e-17 1.19e-04 2.00e-04 9.90e-01 4 -6.4286e-01 -6.4288e-01 2.63e-05 6.72e-17 3.63e-17 1.23e-06 2.06e-06 9.90e-01 5 -6.4286e-01 -6.4286e-01 2.63e-07 8.83e-15 1.81e-14 1.23e-08 2.06e-08 9.90e-01 6 -6.4286e-01 -6.4286e-01 2.63e-09 1.73e-16 3.30e-16 1.23e-10 2.06e-10 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 85µs test_basic_qp.R............... 0 tests test_basic_qp.R............... 1 tests OK test_basic_qp.R............... 2 tests OK test_basic_qp.R............... 2 tests OK test_basic_qp.R............... 2 tests OK test_basic_qp.R............... 2 tests OK cones: [NonnegativeConeT(3), NonnegativeConeT(3)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 2 constraints = 6 nnz(P) = 3 nnz(A) = 8 cones (total) = 2 : Nonnegative = 2, numel = (3,3) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +8.9060e-01 -1.3057e+00 2.20e+00 4.70e-01 2.87e-16 1.00e+00 2.47e+00 ------ 1 +1.4696e+00 +1.0134e+00 4.50e-01 1.03e-01 1.74e-16 1.48e-01 6.24e-01 8.06e-01 2 +1.8977e+00 +1.8463e+00 2.78e-02 1.86e-03 1.41e-16 8.33e-03 3.51e-02 9.90e-01 3 +1.8851e+00 +1.8753e+00 5.21e-03 6.02e-05 2.36e-16 1.20e-03 4.42e-03 9.72e-01 4 +1.8811e+00 +1.8791e+00 1.07e-03 7.30e-06 1.19e-16 2.53e-04 7.58e-04 8.89e-01 5 +1.8802e+00 +1.8799e+00 1.50e-04 7.65e-07 8.62e-17 3.62e-05 9.79e-05 8.99e-01 6 +1.8800e+00 +1.8800e+00 5.24e-06 2.11e-08 8.65e-17 1.28e-06 3.36e-06 9.73e-01 7 +1.8800e+00 +1.8800e+00 5.71e-08 2.25e-10 1.22e-16 1.40e-08 3.67e-08 9.89e-01 8 +1.8800e+00 +1.8800e+00 5.72e-10 2.25e-12 6.12e-15 1.40e-10 3.67e-10 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 83µs test_basic_qp.R............... 2 tests OK test_basic_qp.R............... 3 tests OK test_basic_qp.R............... 3 tests OK test_basic_qp.R............... 4 tests OK test_basic_qp.R............... 4 tests OK test_basic_qp.R............... 5 tests OK test_basic_qp.R............... 6 tests OK test_basic_qp.R............... 6 tests OK test_basic_qp.R............... 6 tests OK test_basic_qp.R............... 6 tests OK cones: [NonnegativeConeT(3), NonnegativeConeT(3)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 2 constraints = 6 nnz(P) = 3 nnz(A) = 8 cones (total) = 2 : Nonnegative = 2, numel = (3,3) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +1.2503e-01 +7.5480e+00 7.42e+00 7.33e-01 1.46e-16 1.00e+00 3.97e+00 ------ 1 +1.1897e+02 +2.1160e+02 7.79e-01 7.66e-01 3.15e-16 1.64e+02 8.73e-01 8.05e-01 2 +1.1856e+01 +5.3261e+03 4.48e+02 7.88e-01 1.28e-16 5.45e+03 1.87e-02 9.90e-01 3 +1.1302e+01 +5.1961e+05 4.60e+04 7.87e-01 3.24e-16 5.20e+05 1.88e-04 9.90e-01 4 +1.1302e+01 +5.1964e+07 4.60e+06 7.87e-01 2.63e-16 5.20e+07 1.88e-06 9.90e-01 5 +1.1301e+01 +5.1955e+09 4.60e+08 7.87e-01 2.90e-16 5.20e+09 1.88e-08 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = PrimalInfeasible solve time = 81µs test_basic_qp.R............... 6 tests OK test_basic_qp.R............... 7 tests OK test_basic_qp.R............... 8 tests OK test_basic_qp.R............... 9 tests OK test_basic_qp.R............... 9 tests OK cones: [NonnegativeConeT(2)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 2 constraints = 2 nnz(P) = 3 nnz(A) = 3 cones (total) = 1 : Nonnegative = 1, numel = 2 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 -2.5000e+00 -4.5000e+00 8.00e-01 2.21e-01 1.05e+00 1.00e+00 2.33e+00 ------ 1 +9.9417e+02 -1.3548e+03 2.36e+00 1.16e-01 5.87e-01 1.55e+02 5.98e-01 7.85e-01 2 +9.4657e+01 -3.0434e+02 4.22e+00 7.35e-03 5.23e-02 3.54e+02 8.07e-02 9.90e-01 3 -1.0831e+03 -9.3717e+02 1.56e-01 4.04e-04 3.20e-03 9.21e+02 1.35e-02 9.32e-01 4 +1.1410e+06 -1.3694e+06 2.20e+00 1.10e-05 8.82e-05 8.96e+04 1.64e-03 9.90e-01 5 +1.8559e+05 -7.5013e+05 5.04e+00 1.43e-06 1.16e-05 8.89e+04 3.69e-04 7.99e-01 6 +1.5044e+09 -1.6326e+09 2.09e+00 1.93e-07 1.56e-06 2.11e+07 1.66e-04 9.18e-01 7 +3.0492e+08 -4.9259e+08 2.62e+00 5.93e-09 4.80e-08 8.18e+06 1.28e-05 9.68e-01 8 -5.4440e+08 -7.2422e+08 3.30e-01 2.66e-10 3.56e-09 1.09e+08 3.37e-06 9.90e-01 9 +1.1034e+12 -1.2297e+12 2.11e+00 1.59e-11 1.97e-10 1.01e+10 4.57e-07 9.41e-01 10 +1.8191e+11 -3.6212e+11 2.99e+00 1.58e-13 1.26e-11 3.73e+09 4.75e-08 9.90e-01 11 -1.5112e+11 -2.0438e+11 3.52e-01 1.52e-15 5.64e-12 2.34e+09 6.70e-09 9.90e-01 12 +3.6829e+14 -4.0384e+14 2.10e+00 2.36e-16 5.80e-14 2.33e+11 1.31e-09 8.89e-01 13 +6.6629e+13 -1.1676e+14 2.75e+00 4.15e-15 4.02e-14 8.53e+10 1.91e-10 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = DualInfeasible solve time = 92.2µs test_basic_qp.R............... 9 tests OK test_basic_qp.R............... 10 tests OK test_basic_qp.R............... 11 tests OK test_basic_qp.R............... 12 tests OK test_basic_qp.R............... 12 tests OK test_basic_qp.R............... 12 tests OK test_basic_qp.R............... 12 tests OK test_basic_qp.R............... 12 tests OK cones: [NonnegativeConeT(1)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 2 constraints = 1 nnz(P) = 3 nnz(A) = 2 cones (total) = 1 : Nonnegative = 1, numel = 1 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 -4.0000e+08 -1.1250e+00 3.56e+08 1.77e-09 9.01e-09 1.00e+00 1.00e+00 ------ 1 -1.3600e+10 -6.1163e+02 2.22e+07 1.77e-09 7.50e-09 2.08e+02 2.21e-01 7.54e-01 2 -1.3215e+12 -3.3922e+06 3.90e+05 1.77e-09 7.50e-09 8.17e+06 2.02e-01 3.35e-01 3 -5.1435e+08 -9.5747e-02 5.14e+08 3.93e-10 4.23e-09 4.00e+08 2.67e+08 5.50e-02 4 +1.3585e+16 -1.3585e+16 2.00e+00 9.30e-11 3.96e-10 5.72e+10 1.81e+12 7.27e-01 --------------------------------------------------------------------------------------------- Terminated with status = DualInfeasible solve time = 48.2µs test_basic_qp.R............... 12 tests OK test_basic_qp.R............... 13 tests OK test_basic_qp.R............... 14 tests OK test_basic_qp.R............... 15 tests OK 33ms test_basic_socp.R............. 0 tests test_basic_socp.R............. 0 tests test_basic_socp.R............. 0 tests test_basic_socp.R............. 0 tests cones: [NonnegativeConeT(3), NonnegativeConeT(3), SecondOrderConeT(3)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 3 constraints = 9 nnz(P) = 6 nnz(A) = 9 cones (total) = 3 : Nonnegative = 2, numel = (3,3) : SecondOrder = 1, numel = 3 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 -3.7996e-01 -7.5303e+00 7.15e+00 5.28e-01 4.03e-01 1.00e+00 2.25e+00 ------ 1 -5.2450e-01 -1.1151e+00 5.91e-01 7.33e-02 6.20e-02 1.11e-01 3.88e-01 9.53e-01 2 -8.2395e-01 -9.6864e-01 1.45e-01 4.43e-03 3.94e-03 2.04e-02 5.87e-02 9.90e-01 3 -8.4516e-01 -8.5575e-01 1.06e-02 2.93e-04 2.50e-04 1.55e-03 4.20e-03 9.43e-01 4 -8.4574e-01 -8.4719e-01 1.46e-03 3.89e-05 3.29e-05 2.07e-04 5.70e-04 8.75e-01 5 -8.4589e-01 -8.4601e-01 1.22e-04 2.44e-06 2.07e-06 1.36e-05 4.40e-05 9.90e-01 6 -8.4590e-01 -8.4590e-01 2.62e-06 4.89e-08 4.14e-08 2.79e-07 9.35e-07 9.80e-01 7 -8.4590e-01 -8.4590e-01 6.48e-08 5.71e-10 4.83e-10 4.64e-09 2.11e-08 9.90e-01 8 -8.4590e-01 -8.4590e-01 1.74e-09 1.29e-11 4.97e-12 8.13e-11 5.29e-10 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 155.3µs test_basic_socp.R............. 0 tests test_basic_socp.R............. 1 tests OK test_basic_socp.R............. 2 tests OK test_basic_socp.R............. 3 tests OK test_basic_socp.R............. 4 tests OK test_basic_socp.R............. 4 tests OK test_basic_socp.R............. 4 tests OK cones: [NonnegativeConeT(3), NonnegativeConeT(3), SecondOrderConeT(3)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 3 constraints = 9 nnz(P) = 6 nnz(A) = 9 cones (total) = 3 : Nonnegative = 2, numel = (3,3) : SecondOrder = 1, numel = 3 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +3.5499e+00 +2.7772e+02 7.72e+01 6.91e-01 2.74e-01 1.00e+00 4.73e+01 ------ 1 +8.5243e+03 -1.9938e+03 5.28e+00 8.22e-01 1.11e-01 2.60e+02 1.21e+01 7.66e-01 2 +2.2194e+06 -1.6580e+06 2.34e+00 8.41e-01 2.07e-02 1.55e+05 2.06e+00 8.40e-01 3 +6.4996e+07 -1.0284e+07 7.32e+00 8.43e-01 1.15e-03 2.43e+07 1.13e-01 9.46e-01 4 +2.1008e+03 +4.1147e+07 1.96e+04 8.87e-01 1.32e-05 1.24e+08 1.32e-03 9.90e-01 5 -9.0132e-01 +7.8046e+07 7.80e+07 7.88e-01 5.10e-07 6.30e+07 5.10e-05 9.61e-01 6 +2.5440e-01 +7.6508e+09 7.65e+09 7.75e-01 5.42e-09 5.56e+09 5.45e-07 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = PrimalInfeasible solve time = 113.8µs test_basic_socp.R............. 4 tests OK test_basic_socp.R............. 5 tests OK test_basic_socp.R............. 6 tests OK test_basic_socp.R............. 7 tests OK test_basic_socp.R............. 7 tests OK test_basic_socp.R............. 7 tests OK test_basic_socp.R............. 7 tests OK test_basic_socp.R............. 7 tests OK test_basic_socp.R............. 7 tests OK test_basic_socp.R............. 7 tests OK cones: [SecondOrderConeT(3)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 2 constraints = 3 nnz(P) = 1 nnz(A) = 2 cones (total) = 1 : SecondOrder = 1, numel = 3 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +4.9292e-01 -1.2888e-01 6.22e-01 1.79e-01 6.48e-17 1.00e+00 2.35e+00 ------ 1 +9.3926e-01 +7.9266e-01 1.47e-01 6.38e-03 1.08e-16 4.74e-02 1.60e-01 9.67e-01 2 +9.9952e-01 +9.9654e-01 2.97e-03 6.30e-05 1.07e-16 8.14e-04 2.68e-03 9.90e-01 3 +1.0000e+00 +9.9997e-01 2.98e-05 6.30e-07 5.33e-17 8.16e-06 2.69e-05 9.90e-01 4 +1.0000e+00 +1.0000e+00 2.98e-07 6.30e-09 8.73e-15 8.16e-08 2.69e-07 9.90e-01 5 +1.0000e+00 +1.0000e+00 2.98e-09 6.30e-11 1.60e-16 8.16e-10 2.69e-09 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 61.3µs test_basic_socp.R............. 7 tests OK test_basic_socp.R............. 8 tests OK test_basic_socp.R............. 9 tests OK 27ms test_basic_unconstrained.R.... 0 tests test_basic_unconstrained.R.... 0 tests test_basic_unconstrained.R.... 0 tests test_basic_unconstrained.R.... 0 tests test_basic_unconstrained.R.... 0 tests cones: [] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 3 constraints = 0 nnz(P) = 3 nnz(A) = 0 cones (total) = 0 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 -7.0000e+00 -7.0000e+00 2.54e-16 0.00e+00 1.21e-17 1.00e+00 1.00e+00 ------ 0 -7.0000e+00 -7.0000e+00 2.54e-16 0.00e+00 1.21e-17 1.00e+00 1.00e+00 ------ --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 23.7µs test_basic_unconstrained.R.... 0 tests test_basic_unconstrained.R.... 1 tests OK test_basic_unconstrained.R.... 1 tests OK test_basic_unconstrained.R.... 2 tests OK test_basic_unconstrained.R.... 2 tests OK test_basic_unconstrained.R.... 2 tests OK test_basic_unconstrained.R.... 2 tests OK test_basic_unconstrained.R.... 2 tests OK test_basic_unconstrained.R.... 2 tests OK cones: [] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 3 constraints = 0 nnz(P) = 0 nnz(A) = 0 cones (total) = 0 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -0.0000e+00 0.00e+00 0.00e+00 1.00e+00 1.00e+00 1.00e+00 ------ 1 -9.9000e+01 -0.0000e+00 9.90e+01 0.00e+00 1.00e-02 1.00e+02 1.00e-02 9.90e-01 2 -9.9990e+03 -0.0000e+00 1.00e+04 0.00e+00 1.00e-04 1.00e+04 1.00e-04 9.90e-01 3 -1.0000e+06 -0.0000e+00 1.00e+06 0.00e+00 1.00e-06 1.00e+06 1.00e-06 9.90e-01 4 -1.0000e+08 -0.0000e+00 1.00e+08 0.00e+00 1.00e-08 1.00e+08 1.00e-08 9.90e-01 5 -1.0000e+10 -0.0000e+00 1.00e+10 0.00e+00 1.00e-10 1.00e+10 1.00e-10 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = DualInfeasible solve time = 39.4µs test_basic_unconstrained.R.... 2 tests OK test_basic_unconstrained.R.... 3 tests OK 6ms test_mixed_conic.R............ 0 tests test_mixed_conic.R............ 0 tests test_mixed_conic.R............ 0 tests test_mixed_conic.R............ 0 tests test_mixed_conic.R............ 0 tests test_mixed_conic.R............ 0 tests test_mixed_conic.R............ 0 tests cones: [ZeroConeT(3), NonnegativeConeT(3), SecondOrderConeT(3), ExponentialConeT, PowerConeT(0.5)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 3 constraints = 15 nnz(P) = 3 nnz(A) = 15 cones (total) = 5 : Zero = 1, numel = 3 : Nonnegative = 1, numel = 3 : SecondOrder = 1, numel = 3 : Exponential = 1, numel = 3 : Power = 1, numel = 3 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -0.0000e+00 0.00e+00 1.00e+00 1.42e+00 1.00e+00 1.00e+00 ------ 1 -6.1260e-15 -6.7168e-30 6.13e-15 8.77e-02 2.17e-02 2.77e-02 2.77e-02 9.80e-01 2 -5.3305e-15 -5.1813e-30 5.33e-15 2.43e-03 5.91e-04 7.70e-04 7.70e-04 9.80e-01 3 -5.2806e-15 -5.0913e-30 5.28e-15 6.75e-05 1.64e-05 2.13e-05 2.13e-05 9.80e-01 4 -2.1098e-12 -7.4635e-25 2.11e-12 1.87e-06 4.54e-07 5.92e-07 5.92e-07 9.80e-01 5 -1.0801e-13 -1.9516e-27 1.08e-13 5.20e-08 1.26e-08 1.64e-08 1.64e-08 9.80e-01 6 -3.0153e-15 -1.5217e-30 3.02e-15 1.44e-09 3.50e-10 4.56e-10 4.56e-10 9.80e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 106.5µs test_mixed_conic.R............ 0 tests test_mixed_conic.R............ 1 tests OK test_mixed_conic.R............ 2 tests OK 3ms test_presolve.R............... 0 tests test_presolve.R............... 0 tests test_presolve.R............... 0 tests cones: [NonnegativeConeT(3), NonnegativeConeT(3)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- presolve: removed 1 constraints problem: variables = 3 constraints = 5 nnz(P) = 3 nnz(A) = 5 cones (total) = 2 : Nonnegative = 2, numel = (3,2) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 -9.8811e-01 -9.4227e+00 8.43e+00 3.17e-01 3.73e-01 1.00e+00 1.52e+00 ------ 1 -4.2577e+00 -7.9472e+00 8.67e-01 3.67e-02 5.81e-02 5.83e-01 3.14e-01 8.93e-01 2 -5.2213e+00 -6.4568e+00 2.37e-01 8.17e-04 1.76e-03 1.17e-01 3.96e-02 9.90e-01 3 -5.6693e+00 -5.7783e+00 1.92e-02 2.12e-05 4.75e-05 6.68e-03 2.95e-03 9.81e-01 4 -5.7435e+00 -5.7520e+00 1.47e-03 2.37e-07 5.33e-07 4.80e-04 1.98e-04 9.90e-01 5 -5.7499e+00 -5.7500e+00 2.75e-05 2.39e-09 5.38e-09 8.97e-06 3.62e-06 9.90e-01 6 -5.7500e+00 -5.7500e+00 2.80e-07 2.38e-11 5.38e-11 9.12e-08 3.68e-08 9.90e-01 7 -5.7500e+00 -5.7500e+00 2.80e-09 2.38e-13 5.38e-13 9.12e-10 3.69e-10 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 69.2µs test_presolve.R............... 0 tests test_presolve.R............... 1 tests OK test_presolve.R............... 2 tests OK test_presolve.R............... 2 tests OK test_presolve.R............... 2 tests OK cones: [NonnegativeConeT(3), NonnegativeConeT(3)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- presolve: removed 3 constraints problem: variables = 3 constraints = 3 nnz(P) = 3 nnz(A) = 3 cones (total) = 1 : Nonnegative = 1, numel = 3 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 -2.8250e+00 -8.3917e+00 1.97e+00 5.47e-01 4.22e-01 1.00e+00 2.12e+00 ------ 1 +7.3025e+00 -1.3831e+01 2.89e+00 7.17e-03 1.00e-02 1.68e+00 2.56e-01 9.90e-01 2 -1.3535e+00 -5.6563e+00 3.18e+00 1.37e-04 1.76e-04 3.93e-01 3.59e-02 9.90e-01 3 -3.3167e+00 -4.0089e+00 2.09e-01 1.87e-06 2.29e-06 6.61e-02 4.34e-03 9.90e-01 4 -3.6886e+00 -3.7730e+00 2.29e-02 2.10e-08 2.55e-08 7.30e-03 4.31e-04 9.90e-01 5 -3.7458e+00 -3.7512e+00 1.45e-03 2.21e-10 2.68e-10 4.48e-04 2.50e-05 9.90e-01 6 -3.7499e+00 -3.7500e+00 2.27e-05 2.22e-12 2.69e-12 7.04e-06 3.87e-07 9.90e-01 7 -3.7500e+00 -3.7500e+00 2.29e-07 3.36e-14 2.09e-13 7.10e-08 3.91e-09 9.90e-01 8 -3.7500e+00 -3.7500e+00 2.29e-09 8.00e-16 4.37e-15 7.10e-10 3.91e-11 9.90e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 46.4µs test_presolve.R............... 2 tests OK test_presolve.R............... 3 tests OK test_presolve.R............... 4 tests OK test_presolve.R............... 4 tests OK test_presolve.R............... 5 tests OK test_presolve.R............... 5 tests OK test_presolve.R............... 5 tests OK cones: [NonnegativeConeT(3), NonnegativeConeT(3)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- presolve: removed 6 constraints problem: variables = 3 constraints = 0 nnz(P) = 3 nnz(A) = 0 cones (total) = 0 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 200, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 -7.0000e+00 -7.0000e+00 2.54e-16 0.00e+00 1.21e-17 1.00e+00 1.00e+00 ------ 0 -7.0000e+00 -7.0000e+00 2.54e-16 0.00e+00 1.21e-17 1.00e+00 1.00e+00 ------ --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 16.3µs test_presolve.R............... 5 tests OK test_presolve.R............... 6 tests OK test_presolve.R............... 7 tests OK 5ms test_sdp_chordal.R............ 0 tests test_sdp_chordal.R............ 0 tests test_sdp_chordal.R............ 0 tests test_sdp_chordal.R............ 0 tests cones: [NonnegativeConeT(1), PSDTriangleConeT(6), PowerConeT(0.3333333333333333), PowerConeT(0.5)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- chordal decomposition: compact format = false, dual completion = false merge method = clique_graph PSD cones initial = 1 PSD cones decomposable = 1 PSD cones after decomposition = 3 PSD cones after merges = 3 problem: variables = 34 constraints = 54 nnz(P) = 0 nnz(A) = 68 cones (total) = 7 : Zero = 1, numel = 28 : Nonnegative = 1, numel = 1 : Power = 2, numel = (3,3) : PSDTriangle = 3, numel = (10,6,3) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 50, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -0.0000e+00 0.00e+00 1.01e+00 8.25e-01 1.00e+00 1.00e+00 ------ 1 -1.4610e-01 +2.6604e-01 4.12e-01 3.46e-01 2.25e-01 9.62e-01 3.54e-01 6.99e-01 2 -1.0335e-01 -1.2769e-02 9.06e-02 1.07e-01 9.23e-02 2.95e-01 1.75e-01 6.34e-01 3 -1.0223e+00 -9.1540e-01 1.07e-01 3.63e-02 3.07e-02 2.06e-01 6.49e-02 7.92e-01 4 -1.4436e+00 -1.4024e+00 2.94e-02 8.33e-03 7.13e-03 6.92e-02 1.59e-02 7.92e-01 5 -1.6883e+00 -1.6854e+00 1.72e-03 5.42e-04 4.65e-04 4.88e-03 1.04e-03 9.80e-01 6 -1.7054e+00 -1.7048e+00 3.65e-04 1.16e-04 9.95e-05 1.05e-03 2.24e-04 7.92e-01 7 -1.7099e+00 -1.7098e+00 9.24e-06 3.23e-06 2.76e-06 2.77e-05 6.21e-06 9.80e-01 8 -1.7100e+00 -1.7100e+00 2.34e-07 8.97e-08 7.66e-08 7.30e-07 1.72e-07 9.80e-01 9 -1.7100e+00 -1.7100e+00 6.04e-09 2.49e-09 2.12e-09 1.95e-08 4.78e-09 9.80e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 814.6µs ----- PASSED : test_sdp_chordal.R<73--86> call| expect_equal(status_codes[[solution$status]], status_codes[["Solved"]]) cones: [NonnegativeConeT(1), PSDTriangleConeT(6), PowerConeT(0.3333333333333333), PowerConeT(0.5)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 8 constraints = 28 nnz(P) = 0 nnz(A) = 16 cones (total) = 4 : Nonnegative = 1, numel = 1 : Power = 2, numel = (3,3) : PSDTriangle = 1, numel = 21 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 50, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -7.8521e+00 7.85e+00 8.42e-01 1.06e+00 1.00e+00 1.00e+00 ------ 1 -1.2322e-01 -3.9093e+00 3.79e+00 3.04e-01 3.62e-01 1.24e+00 3.10e-01 7.34e-01 2 -1.4564e-01 -1.4298e+00 1.28e+00 7.70e-02 1.41e-01 2.04e-01 1.16e-01 7.41e-01 3 -1.3973e+00 -1.9107e+00 3.67e-01 2.20e-02 3.64e-02 1.64e-01 3.60e-02 8.69e-01 4 -1.6180e+00 -1.7300e+00 6.92e-02 4.63e-03 7.82e-03 3.90e-02 7.71e-03 7.92e-01 5 -1.6901e+00 -1.7143e+00 1.44e-02 9.92e-04 1.67e-03 8.54e-03 1.65e-03 7.92e-01 6 -1.7093e+00 -1.7100e+00 3.95e-04 2.75e-05 4.64e-05 2.39e-04 4.59e-05 9.80e-01 7 -1.7100e+00 -1.7100e+00 1.10e-05 7.64e-07 1.29e-06 6.58e-06 1.27e-06 9.80e-01 8 -1.7100e+00 -1.7100e+00 3.05e-07 2.12e-08 3.57e-08 1.81e-07 3.53e-08 9.80e-01 9 -1.7100e+00 -1.7100e+00 6.54e-08 4.54e-09 7.65e-09 3.89e-08 7.56e-09 7.92e-01 10 -1.7100e+00 -1.7100e+00 1.40e-08 9.73e-10 1.64e-09 8.33e-09 1.62e-09 7.92e-01 11 -1.7100e+00 -1.7100e+00 3.44e-09 2.39e-10 4.02e-10 2.04e-09 3.97e-10 7.92e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 651.8µs ----- PASSED : test_sdp_chordal.R<73--86> call| expect_equal(status_codes[[solution$status]], status_codes[["Solved"]]) cones: [NonnegativeConeT(1), PSDTriangleConeT(6), PowerConeT(0.3333333333333333), PowerConeT(0.5)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- chordal decomposition: compact format = false, dual completion = false merge method = none PSD cones initial = 1 PSD cones decomposable = 1 PSD cones after decomposition = 3 PSD cones after merges = 3 problem: variables = 34 constraints = 54 nnz(P) = 0 nnz(A) = 68 cones (total) = 7 : Zero = 1, numel = 28 : Nonnegative = 1, numel = 1 : Power = 2, numel = (3,3) : PSDTriangle = 3, numel = (6,10,3) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 50, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -0.0000e+00 0.00e+00 1.01e+00 8.25e-01 1.00e+00 1.00e+00 ------ 1 -1.4610e-01 +2.6604e-01 4.12e-01 3.46e-01 2.25e-01 9.62e-01 3.54e-01 6.99e-01 2 -1.0335e-01 -1.2769e-02 9.06e-02 1.07e-01 9.23e-02 2.95e-01 1.75e-01 6.34e-01 3 -1.0223e+00 -9.1540e-01 1.07e-01 3.63e-02 3.07e-02 2.06e-01 6.49e-02 7.92e-01 4 -1.4436e+00 -1.4024e+00 2.94e-02 8.33e-03 7.13e-03 6.92e-02 1.59e-02 7.92e-01 5 -1.6883e+00 -1.6854e+00 1.72e-03 5.42e-04 4.65e-04 4.88e-03 1.04e-03 9.80e-01 6 -1.7054e+00 -1.7048e+00 3.65e-04 1.16e-04 9.95e-05 1.05e-03 2.24e-04 7.92e-01 7 -1.7099e+00 -1.7098e+00 9.24e-06 3.23e-06 2.76e-06 2.77e-05 6.21e-06 9.80e-01 8 -1.7100e+00 -1.7100e+00 2.34e-07 8.97e-08 7.66e-08 7.30e-07 1.72e-07 9.80e-01 9 -1.7100e+00 -1.7100e+00 6.04e-09 2.49e-09 2.12e-09 1.95e-08 4.78e-09 9.80e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 1.0281ms ----- PASSED : test_sdp_chordal.R<73--86> call| expect_equal(status_codes[[solution$status]], status_codes[["Solved"]]) cones: [NonnegativeConeT(1), PSDTriangleConeT(6), PowerConeT(0.3333333333333333), PowerConeT(0.5)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- chordal decomposition: compact format = false, dual completion = on merge method = clique_graph PSD cones initial = 1 PSD cones decomposable = 1 PSD cones after decomposition = 3 PSD cones after merges = 3 problem: variables = 34 constraints = 54 nnz(P) = 0 nnz(A) = 68 cones (total) = 7 : Zero = 1, numel = 28 : Nonnegative = 1, numel = 1 : Power = 2, numel = (3,3) : PSDTriangle = 3, numel = (10,6,3) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 50, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -0.0000e+00 0.00e+00 1.01e+00 8.25e-01 1.00e+00 1.00e+00 ------ 1 -1.4610e-01 +2.6604e-01 4.12e-01 3.46e-01 2.25e-01 9.62e-01 3.54e-01 6.99e-01 2 -1.0335e-01 -1.2769e-02 9.06e-02 1.07e-01 9.23e-02 2.95e-01 1.75e-01 6.34e-01 3 -1.0223e+00 -9.1540e-01 1.07e-01 3.63e-02 3.07e-02 2.06e-01 6.49e-02 7.92e-01 4 -1.4436e+00 -1.4024e+00 2.94e-02 8.33e-03 7.13e-03 6.92e-02 1.59e-02 7.92e-01 5 -1.6883e+00 -1.6854e+00 1.72e-03 5.42e-04 4.65e-04 4.88e-03 1.04e-03 9.80e-01 6 -1.7054e+00 -1.7048e+00 3.65e-04 1.16e-04 9.95e-05 1.05e-03 2.24e-04 7.92e-01 7 -1.7099e+00 -1.7098e+00 9.24e-06 3.23e-06 2.76e-06 2.77e-05 6.21e-06 9.80e-01 8 -1.7100e+00 -1.7100e+00 2.34e-07 8.97e-08 7.66e-08 7.30e-07 1.72e-07 9.80e-01 9 -1.7100e+00 -1.7100e+00 6.04e-09 2.49e-09 2.12e-09 1.95e-08 4.78e-09 9.80e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 1.0317ms ----- PASSED : test_sdp_chordal.R<73--86> call| expect_equal(status_codes[[solution$status]], status_codes[["Solved"]]) cones: [NonnegativeConeT(1), PSDTriangleConeT(6), PowerConeT(0.3333333333333333), PowerConeT(0.5)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 8 constraints = 28 nnz(P) = 0 nnz(A) = 16 cones (total) = 4 : Nonnegative = 1, numel = 1 : Power = 2, numel = (3,3) : PSDTriangle = 1, numel = 21 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 50, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -7.8521e+00 7.85e+00 8.42e-01 1.06e+00 1.00e+00 1.00e+00 ------ 1 -1.2322e-01 -3.9093e+00 3.79e+00 3.04e-01 3.62e-01 1.24e+00 3.10e-01 7.34e-01 2 -1.4564e-01 -1.4298e+00 1.28e+00 7.70e-02 1.41e-01 2.04e-01 1.16e-01 7.41e-01 3 -1.3973e+00 -1.9107e+00 3.67e-01 2.20e-02 3.64e-02 1.64e-01 3.60e-02 8.69e-01 4 -1.6180e+00 -1.7300e+00 6.92e-02 4.63e-03 7.82e-03 3.90e-02 7.71e-03 7.92e-01 5 -1.6901e+00 -1.7143e+00 1.44e-02 9.92e-04 1.67e-03 8.54e-03 1.65e-03 7.92e-01 6 -1.7093e+00 -1.7100e+00 3.95e-04 2.75e-05 4.64e-05 2.39e-04 4.59e-05 9.80e-01 7 -1.7100e+00 -1.7100e+00 1.10e-05 7.64e-07 1.29e-06 6.58e-06 1.27e-06 9.80e-01 8 -1.7100e+00 -1.7100e+00 3.05e-07 2.12e-08 3.57e-08 1.81e-07 3.53e-08 9.80e-01 9 -1.7100e+00 -1.7100e+00 6.54e-08 4.54e-09 7.65e-09 3.89e-08 7.56e-09 7.92e-01 10 -1.7100e+00 -1.7100e+00 1.40e-08 9.73e-10 1.64e-09 8.33e-09 1.62e-09 7.92e-01 11 -1.7100e+00 -1.7100e+00 3.44e-09 2.39e-10 4.02e-10 2.04e-09 3.97e-10 7.92e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 980.3µs ----- PASSED : test_sdp_chordal.R<73--86> call| expect_equal(status_codes[[solution$status]], status_codes[["Solved"]]) cones: [NonnegativeConeT(1), PSDTriangleConeT(6), PowerConeT(0.3333333333333333), PowerConeT(0.5)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- chordal decomposition: compact format = false, dual completion = on merge method = none PSD cones initial = 1 PSD cones decomposable = 1 PSD cones after decomposition = 3 PSD cones after merges = 3 problem: variables = 34 constraints = 54 nnz(P) = 0 nnz(A) = 68 cones (total) = 7 : Zero = 1, numel = 28 : Nonnegative = 1, numel = 1 : Power = 2, numel = (3,3) : PSDTriangle = 3, numel = (6,10,3) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 50, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -0.0000e+00 0.00e+00 1.01e+00 8.25e-01 1.00e+00 1.00e+00 ------ 1 -1.4610e-01 +2.6604e-01 4.12e-01 3.46e-01 2.25e-01 9.62e-01 3.54e-01 6.99e-01 2 -1.0335e-01 -1.2769e-02 9.06e-02 1.07e-01 9.23e-02 2.95e-01 1.75e-01 6.34e-01 3 -1.0223e+00 -9.1540e-01 1.07e-01 3.63e-02 3.07e-02 2.06e-01 6.49e-02 7.92e-01 4 -1.4436e+00 -1.4024e+00 2.94e-02 8.33e-03 7.13e-03 6.92e-02 1.59e-02 7.92e-01 5 -1.6883e+00 -1.6854e+00 1.72e-03 5.42e-04 4.65e-04 4.88e-03 1.04e-03 9.80e-01 6 -1.7054e+00 -1.7048e+00 3.65e-04 1.16e-04 9.95e-05 1.05e-03 2.24e-04 7.92e-01 7 -1.7099e+00 -1.7098e+00 9.24e-06 3.23e-06 2.76e-06 2.77e-05 6.21e-06 9.80e-01 8 -1.7100e+00 -1.7100e+00 2.34e-07 8.97e-08 7.66e-08 7.30e-07 1.72e-07 9.80e-01 9 -1.7100e+00 -1.7100e+00 6.04e-09 2.49e-09 2.12e-09 1.95e-08 4.78e-09 9.80e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 951.2µs ----- PASSED : test_sdp_chordal.R<73--86> call| expect_equal(status_codes[[solution$status]], status_codes[["Solved"]]) cones: [NonnegativeConeT(1), PSDTriangleConeT(6), PowerConeT(0.3333333333333333), PowerConeT(0.5)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- chordal decomposition: compact format = on, dual completion = false merge method = clique_graph PSD cones initial = 1 PSD cones decomposable = 1 PSD cones after decomposition = 3 PSD cones after merges = 3 problem: variables = 12 constraints = 26 nnz(P) = 0 nnz(A) = 24 cones (total) = 6 : Nonnegative = 1, numel = 1 : Power = 2, numel = (3,3) : PSDTriangle = 3, numel = (3,6,10) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 50, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -7.9000e+00 7.90e+00 8.32e-01 9.69e-01 1.00e+00 1.00e+00 ------ 1 -1.3178e-01 -4.0108e+00 3.88e+00 3.22e-01 3.48e-01 9.32e-01 3.53e-01 7.01e-01 2 -2.6545e-01 -1.8655e+00 1.60e+00 1.04e-01 1.57e-01 3.46e-01 1.78e-01 6.34e-01 3 -1.1369e+00 -1.5826e+00 3.92e-01 2.27e-02 3.53e-02 1.55e-01 4.36e-02 7.92e-01 4 -1.5326e+00 -1.6503e+00 7.68e-02 5.64e-03 9.10e-03 5.05e-02 1.07e-02 7.92e-01 5 -1.6766e+00 -1.7031e+00 1.58e-02 1.24e-03 1.95e-03 1.22e-02 2.29e-03 7.92e-01 6 -1.7027e+00 -1.7084e+00 3.39e-03 2.67e-04 4.17e-04 2.66e-03 4.91e-04 7.92e-01 7 -1.7097e+00 -1.7099e+00 9.72e-05 7.42e-06 1.16e-05 6.87e-05 1.36e-05 9.80e-01 8 -1.7100e+00 -1.7100e+00 2.77e-06 2.06e-07 3.21e-07 1.77e-06 3.78e-07 9.80e-01 9 -1.7100e+00 -1.7100e+00 7.86e-08 5.71e-09 8.90e-09 4.64e-08 1.05e-08 9.80e-01 10 -1.7100e+00 -1.7100e+00 2.92e-08 2.12e-09 3.31e-09 1.72e-08 3.89e-09 6.34e-01 11 -1.7100e+00 -1.7100e+00 1.16e-08 8.40e-10 1.31e-09 6.74e-09 1.54e-09 6.34e-01 12 -1.7100e+00 -1.7100e+00 2.86e-09 2.06e-10 3.20e-10 1.62e-09 3.77e-10 7.92e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 1.0279ms ----- PASSED : test_sdp_chordal.R<73--86> call| expect_equal(status_codes[[solution$status]], status_codes[["Solved"]]) cones: [NonnegativeConeT(1), PSDTriangleConeT(6), PowerConeT(0.3333333333333333), PowerConeT(0.5)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 8 constraints = 28 nnz(P) = 0 nnz(A) = 16 cones (total) = 4 : Nonnegative = 1, numel = 1 : Power = 2, numel = (3,3) : PSDTriangle = 1, numel = 21 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 50, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -7.8521e+00 7.85e+00 8.42e-01 1.06e+00 1.00e+00 1.00e+00 ------ 1 -1.2322e-01 -3.9093e+00 3.79e+00 3.04e-01 3.62e-01 1.24e+00 3.10e-01 7.34e-01 2 -1.4564e-01 -1.4298e+00 1.28e+00 7.70e-02 1.41e-01 2.04e-01 1.16e-01 7.41e-01 3 -1.3973e+00 -1.9107e+00 3.67e-01 2.20e-02 3.64e-02 1.64e-01 3.60e-02 8.69e-01 4 -1.6180e+00 -1.7300e+00 6.92e-02 4.63e-03 7.82e-03 3.90e-02 7.71e-03 7.92e-01 5 -1.6901e+00 -1.7143e+00 1.44e-02 9.92e-04 1.67e-03 8.54e-03 1.65e-03 7.92e-01 6 -1.7093e+00 -1.7100e+00 3.95e-04 2.75e-05 4.64e-05 2.39e-04 4.59e-05 9.80e-01 7 -1.7100e+00 -1.7100e+00 1.10e-05 7.64e-07 1.29e-06 6.58e-06 1.27e-06 9.80e-01 8 -1.7100e+00 -1.7100e+00 3.05e-07 2.12e-08 3.57e-08 1.81e-07 3.53e-08 9.80e-01 9 -1.7100e+00 -1.7100e+00 6.54e-08 4.54e-09 7.65e-09 3.89e-08 7.56e-09 7.92e-01 10 -1.7100e+00 -1.7100e+00 1.40e-08 9.73e-10 1.64e-09 8.33e-09 1.62e-09 7.92e-01 11 -1.7100e+00 -1.7100e+00 3.44e-09 2.39e-10 4.02e-10 2.04e-09 3.97e-10 7.92e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 886.4µs ----- PASSED : test_sdp_chordal.R<73--86> call| expect_equal(status_codes[[solution$status]], status_codes[["Solved"]]) cones: [NonnegativeConeT(1), PSDTriangleConeT(6), PowerConeT(0.3333333333333333), PowerConeT(0.5)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- chordal decomposition: compact format = on, dual completion = false merge method = none PSD cones initial = 1 PSD cones decomposable = 1 PSD cones after decomposition = 3 PSD cones after merges = 3 problem: variables = 12 constraints = 26 nnz(P) = 0 nnz(A) = 24 cones (total) = 6 : Nonnegative = 1, numel = 1 : Power = 2, numel = (3,3) : PSDTriangle = 3, numel = (3,10,6) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 50, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -7.8854e+00 7.89e+00 8.32e-01 9.69e-01 1.00e+00 1.00e+00 ------ 1 -1.3178e-01 -4.0029e+00 3.87e+00 3.25e-01 3.52e-01 9.32e-01 3.53e-01 7.01e-01 2 -2.6545e-01 -1.8623e+00 1.60e+00 1.07e-01 1.65e-01 3.46e-01 1.78e-01 6.34e-01 3 -1.1369e+00 -1.5816e+00 3.91e-01 2.30e-02 3.61e-02 1.55e-01 4.36e-02 7.92e-01 4 -1.5326e+00 -1.6501e+00 7.66e-02 5.68e-03 9.27e-03 5.05e-02 1.07e-02 7.92e-01 5 -1.6766e+00 -1.7030e+00 1.57e-02 1.25e-03 1.98e-03 1.22e-02 2.29e-03 7.92e-01 6 -1.7027e+00 -1.7084e+00 3.38e-03 2.69e-04 4.23e-04 2.66e-03 4.91e-04 7.92e-01 7 -1.7097e+00 -1.7099e+00 9.70e-05 7.47e-06 1.17e-05 6.87e-05 1.36e-05 9.80e-01 8 -1.7100e+00 -1.7100e+00 2.77e-06 2.07e-07 3.25e-07 1.77e-06 3.78e-07 9.80e-01 9 -1.7100e+00 -1.7100e+00 7.84e-08 5.75e-09 9.02e-09 4.64e-08 1.05e-08 9.80e-01 10 -1.7100e+00 -1.7100e+00 2.21e-09 1.59e-10 2.50e-10 1.23e-09 2.91e-10 9.80e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 833µs ----- PASSED : test_sdp_chordal.R<73--86> call| expect_equal(status_codes[[solution$status]], status_codes[["Solved"]]) cones: [NonnegativeConeT(1), PSDTriangleConeT(6), PowerConeT(0.3333333333333333), PowerConeT(0.5)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- chordal decomposition: compact format = on, dual completion = on merge method = clique_graph PSD cones initial = 1 PSD cones decomposable = 1 PSD cones after decomposition = 3 PSD cones after merges = 3 problem: variables = 12 constraints = 26 nnz(P) = 0 nnz(A) = 24 cones (total) = 6 : Nonnegative = 1, numel = 1 : Power = 2, numel = (3,3) : PSDTriangle = 3, numel = (3,6,10) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 50, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -7.9000e+00 7.90e+00 8.32e-01 9.69e-01 1.00e+00 1.00e+00 ------ 1 -1.3178e-01 -4.0108e+00 3.88e+00 3.22e-01 3.48e-01 9.32e-01 3.53e-01 7.01e-01 2 -2.6545e-01 -1.8655e+00 1.60e+00 1.04e-01 1.57e-01 3.46e-01 1.78e-01 6.34e-01 3 -1.1369e+00 -1.5826e+00 3.92e-01 2.27e-02 3.53e-02 1.55e-01 4.36e-02 7.92e-01 4 -1.5326e+00 -1.6503e+00 7.68e-02 5.64e-03 9.10e-03 5.05e-02 1.07e-02 7.92e-01 5 -1.6766e+00 -1.7031e+00 1.58e-02 1.24e-03 1.95e-03 1.22e-02 2.29e-03 7.92e-01 6 -1.7027e+00 -1.7084e+00 3.39e-03 2.67e-04 4.17e-04 2.66e-03 4.91e-04 7.92e-01 7 -1.7097e+00 -1.7099e+00 9.72e-05 7.42e-06 1.16e-05 6.87e-05 1.36e-05 9.80e-01 8 -1.7100e+00 -1.7100e+00 2.77e-06 2.06e-07 3.21e-07 1.77e-06 3.78e-07 9.80e-01 9 -1.7100e+00 -1.7100e+00 7.86e-08 5.71e-09 8.90e-09 4.64e-08 1.05e-08 9.80e-01 10 -1.7100e+00 -1.7100e+00 2.92e-08 2.12e-09 3.31e-09 1.72e-08 3.89e-09 6.34e-01 11 -1.7100e+00 -1.7100e+00 1.16e-08 8.40e-10 1.31e-09 6.74e-09 1.54e-09 6.34e-01 12 -1.7100e+00 -1.7100e+00 2.86e-09 2.06e-10 3.20e-10 1.62e-09 3.77e-10 7.92e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 970.7µs ----- PASSED : test_sdp_chordal.R<73--86> call| expect_equal(status_codes[[solution$status]], status_codes[["Solved"]]) cones: [NonnegativeConeT(1), PSDTriangleConeT(6), PowerConeT(0.3333333333333333), PowerConeT(0.5)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- problem: variables = 8 constraints = 28 nnz(P) = 0 nnz(A) = 16 cones (total) = 4 : Nonnegative = 1, numel = 1 : Power = 2, numel = (3,3) : PSDTriangle = 1, numel = 21 settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 50, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -7.8521e+00 7.85e+00 8.42e-01 1.06e+00 1.00e+00 1.00e+00 ------ 1 -1.2322e-01 -3.9093e+00 3.79e+00 3.04e-01 3.62e-01 1.24e+00 3.10e-01 7.34e-01 2 -1.4564e-01 -1.4298e+00 1.28e+00 7.70e-02 1.41e-01 2.04e-01 1.16e-01 7.41e-01 3 -1.3973e+00 -1.9107e+00 3.67e-01 2.20e-02 3.64e-02 1.64e-01 3.60e-02 8.69e-01 4 -1.6180e+00 -1.7300e+00 6.92e-02 4.63e-03 7.82e-03 3.90e-02 7.71e-03 7.92e-01 5 -1.6901e+00 -1.7143e+00 1.44e-02 9.92e-04 1.67e-03 8.54e-03 1.65e-03 7.92e-01 6 -1.7093e+00 -1.7100e+00 3.95e-04 2.75e-05 4.64e-05 2.39e-04 4.59e-05 9.80e-01 7 -1.7100e+00 -1.7100e+00 1.10e-05 7.64e-07 1.29e-06 6.58e-06 1.27e-06 9.80e-01 8 -1.7100e+00 -1.7100e+00 3.05e-07 2.12e-08 3.57e-08 1.81e-07 3.53e-08 9.80e-01 9 -1.7100e+00 -1.7100e+00 6.54e-08 4.54e-09 7.65e-09 3.89e-08 7.56e-09 7.92e-01 10 -1.7100e+00 -1.7100e+00 1.40e-08 9.73e-10 1.64e-09 8.33e-09 1.62e-09 7.92e-01 11 -1.7100e+00 -1.7100e+00 3.44e-09 2.39e-10 4.02e-10 2.04e-09 3.97e-10 7.92e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 802.7µs ----- PASSED : test_sdp_chordal.R<73--86> call| expect_equal(status_codes[[solution$status]], status_codes[["Solved"]]) cones: [NonnegativeConeT(1), PSDTriangleConeT(6), PowerConeT(0.3333333333333333), PowerConeT(0.5)] ------------------------------------------------------------- Clarabel.rs v0.9.0 - Clever Acronym (c) Paul Goulart University of Oxford, 2022 ------------------------------------------------------------- chordal decomposition: compact format = on, dual completion = on merge method = none PSD cones initial = 1 PSD cones decomposable = 1 PSD cones after decomposition = 3 PSD cones after merges = 3 problem: variables = 12 constraints = 26 nnz(P) = 0 nnz(A) = 24 cones (total) = 6 : Nonnegative = 1, numel = 1 : Power = 2, numel = (3,3) : PSDTriangle = 3, numel = (3,10,6) settings: linear algebra: direct / qdldl, precision: 64 bit max iter = 50, time limit = Inf, max step = 0.990 tol_feas = 1.0e-8, tol_gap_abs = 1.0e-8, tol_gap_rel = 1.0e-8, static reg : on, ϵ1 = 1.0e-8, ϵ2 = 4.9e-32 dynamic reg: on, ϵ = 1.0e-13, δ = 2.0e-7 iter refine: on, reltol = 1.0e-13, abstol = 1.0e-12, max iter = 10, stop ratio = 5.0 equilibrate: on, min_scale = 1.0e-4, max_scale = 1.0e4 max iter = 10 iter pcost dcost gap pres dres k/t μ step --------------------------------------------------------------------------------------------- 0 +0.0000e+00 -7.8854e+00 7.89e+00 8.32e-01 9.69e-01 1.00e+00 1.00e+00 ------ 1 -1.3178e-01 -4.0029e+00 3.87e+00 3.25e-01 3.52e-01 9.32e-01 3.53e-01 7.01e-01 2 -2.6545e-01 -1.8623e+00 1.60e+00 1.07e-01 1.65e-01 3.46e-01 1.78e-01 6.34e-01 3 -1.1369e+00 -1.5816e+00 3.91e-01 2.30e-02 3.61e-02 1.55e-01 4.36e-02 7.92e-01 4 -1.5326e+00 -1.6501e+00 7.66e-02 5.68e-03 9.27e-03 5.05e-02 1.07e-02 7.92e-01 5 -1.6766e+00 -1.7030e+00 1.57e-02 1.25e-03 1.98e-03 1.22e-02 2.29e-03 7.92e-01 6 -1.7027e+00 -1.7084e+00 3.38e-03 2.69e-04 4.23e-04 2.66e-03 4.91e-04 7.92e-01 7 -1.7097e+00 -1.7099e+00 9.70e-05 7.47e-06 1.17e-05 6.87e-05 1.36e-05 9.80e-01 8 -1.7100e+00 -1.7100e+00 2.77e-06 2.07e-07 3.25e-07 1.77e-06 3.78e-07 9.80e-01 9 -1.7100e+00 -1.7100e+00 7.84e-08 5.75e-09 9.02e-09 4.64e-08 1.05e-08 9.80e-01 10 -1.7100e+00 -1.7100e+00 2.21e-09 1.59e-10 2.50e-10 1.23e-09 2.91e-10 9.80e-01 --------------------------------------------------------------------------------------------- Terminated with status = Solved solve time = 761.5µs ----- PASSED : test_sdp_chordal.R<73--86> call| expect_equal(status_codes[[solution$status]], status_codes[["Solved"]]) test_sdp_chordal.R............ 12 tests OK 0.1s All ok, 91 results (1.5s) > > proc.time() user system elapsed 1.65 0.18 1.82