R Under development (unstable) (2024-03-01 r86033 ucrt) -- "Unsuffered Consequences"
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> #
> # Test out math aspects
> #
> library(bdsmatrix)

Attaching package: 'bdsmatrix'

The following object is masked from 'package:base':

    backsolve

> aeq <- function(x,y) all.equal(as.vector(x), as.vector(y))
> 
> tmat <- bdsmatrix(c(3,2,2,4), 
+ 	      c(22,1,2,21,3,20,19,4,18,17,5,16,15,6,7, 8,14,9,10,13,11,12),
+ 	      matrix(c(1,0,1,1,0,0,1,1,0,1,0,10,0,
+                        0,1,1,0,1,1,0,1,1,0,1,0,10), ncol=2))
> dimnames(tmat) <- list(NULL, letters[1:13])
> 
> smat <- as.matrix(tmat)
> 
> aeq(smat+2.1, as.matrix(tmat+2.1))
[1] TRUE
> aeq(smat/2.1, as.matrix(tmat/2.1))
[1] TRUE
> aeq(smat-2.1, as.matrix(tmat-2.1))
[1] TRUE
> aeq(smat*2.1, as.matrix(tmat*2.1))
[1] TRUE
> aeq(round(smat,1), as.matrix(round(tmat,1)))
[1] TRUE
> aeq(exp(smat), as.matrix(exp(tmat)))
[1] TRUE
> 
> aeq(sum(smat), sum(tmat))
[1] TRUE
> aeq(prod(smat), prod(tmat))
[1] TRUE
> aeq(sum(smat+3), sum(tmat+3))
[1] TRUE
> aeq(prod(smat+2), prod(tmat+2))
[1] TRUE
> aeq(range(smat), range(tmat))
[1] TRUE
> aeq(max(smat), max(tmat))
[1] TRUE
> aeq(min(smat), min(tmat))
[1] TRUE
> 
> aeq(smat+1:13, tmat+1:13)
[1] TRUE
> aeq(smat+1:13, 1:13 +tmat )
[1] TRUE
> aeq(smat+tmat, 2*smat)
[1] TRUE
> all.equal(tmat+tmat, 2*tmat)
[1] TRUE
> 
> aeq(sort(unique(c(smat))), sort(unique(tmat)))
[1] TRUE
> 
> #
> # check out the alternate input style, with full blocks
> #
> rmat <- bdsmatrix(c(3,2,2,4),
+ 		  c(22,1,2,1,21,3,2,3,20, 19,4,4,18, 17,5,5,16,
+ 		    15,6,7,8,6,14,9,10,7,9,13,11,8,10,11,12),
+ 		  matrix(c(1,0,1,1,0,0,1,1,0,1,0,10,0,
+ 			   0,1,1,0,1,1,0,1,1,0,1,0,10), ncol=2),
+ 		  dimnames=list(NULL, letters[1:13]))
> all.equal(rmat, tmat)
[1] TRUE
> 
> 
> # Do some subscripting
> zz <- c(1,2,7,8,9,11)
> aeq(smat[zz,zz], as.matrix(tmat[zz,zz]))
[1] TRUE
> 
> all.equal(smat[zz, 8:13], tmat[zz, 8:13])  # both are matrices
[1] TRUE
> 
> # Diagonals
> aeq(diag(smat), diag(tmat))
[1] TRUE
> zz <- diag(smat)
> diag(smat) <- zz*2
> diag(tmat) <- zz*2
> all.equal(smat, as.matrix(tmat))
[1] TRUE
> 
> proc.time()
   user  system elapsed 
   0.37    0.00    0.35