R Under development (unstable) (2024-09-02 r87090 ucrt) -- "Unsuffered Consequences" Copyright (C) 2024 The R Foundation for Statistical Computing Platform: x86_64-w64-mingw32/x64 R is free software and comes with ABSOLUTELY NO WARRANTY. You are welcome to redistribute it under certain conditions. Type 'license()' or 'licence()' for distribution details. R is a collaborative project with many contributors. Type 'contributors()' for more information and 'citation()' on how to cite R or R packages in publications. Type 'demo()' for some demos, 'help()' for on-line help, or 'help.start()' for an HTML browser interface to help. Type 'q()' to quit R. > # This file is part of the standard setup for testthat. > # It is recommended that you do not modify it. > # > # Where should you do additional test configuration? > # Learn more about the roles of various files in: > # * https://r-pkgs.org/testing-design.html#sec-tests-files-overview > # * https://testthat.r-lib.org/articles/special-files.html > > library(testthat) > library(CondCopulas) > > test_check("CondCopulas") Kendall regression: Λ(𝜏) = β0 + β' phi(z) where 𝜏 is conditional Kendall's tau between X1 and X2 given Z = z Coefficients: Estimate Std. Error z value p-value Intercept -0.774226 0.053118 -14.5755 <2e-16 *** phi1 0.943523 1.610511 0.5859 0.5580 phi2 0.852636 1.579101 0.5400 0.5892 --- Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1 Wald statistics β' V^{-1} β : 49.16084 Test of the simplifying assumption with 2 DF, pvalue: 2.11281e-11 Kendall regression: Λ(𝜏) = β0 + β' phi(z) where 𝜏 is conditional Kendall's tau between X1 and X2 given Z = z Coefficients: Estimate Std. Error z value p-value Intercept 0.000000 0.973703 0.0000 1.0000 phi1 -0.329603 1.475803 -0.2233 0.8233 phi2 0.000000 0.031827 0.0000 1.0000 phi3 0.000000 0.053129 0.0000 1.0000 phi4 0.000000 0.255144 0.0000 1.0000 phi5 -0.126825 0.300241 -0.4224 0.6727 Wald statistics β' V^{-1} β : 0.2821791 Test of the simplifying assumption with 5 DF, pvalue: 0.9979649 [ FAIL 0 | WARN 0 | SKIP 0 | PASS 25 ] > > proc.time() user system elapsed 112.20 54.42 166.78